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miv72 [106K]
2 years ago
7

List the constant(s) in 2ab + 8 + c - 10

Mathematics
1 answer:
natali 33 [55]2 years ago
4 0

Answer:

Constants: 8 and 10

Step-by-step explanation:

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19038 times 8975765yud
ehidna [41]
1.7088061E11 on a calculator that's what I did

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3 years ago
Write a quadratic equation having the given numbers as solutions. -7 and -5
AlexFokin [52]

Answer:

x²+12x+35

Step-by-step explanation:

in factored form it would just be

(x+7)(x+5)=0

expand this

x²+12x+35=0

6 0
3 years ago
If the diameter of a circle is 9 square roots of 2, what is the circumference?
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3 0
3 years ago
Read 2 more answers
Sal's Sandwich Shop sells wraps and sandwiches as part of its lunch specials. The profit on every sandwich is $2, and the profit
Xelga [282]

Answer:

Answer:

1.) the y intercept is 490 and the slope is -2/3x

2.) First, I would find the point (0,490) and plot a point there. Then I would use our slope -2/3 to figure out what direction and what angle the line goes by counting 2 down and 3 to the right

3.) f(x)= -2/3x+490

The graph represents how many wraps could've been sold for each number of sandwich sales to keep the same profit of $1,470.  

4.) graph down below

5.) the profits are the same (slope) but the y intercept is higher then the original graph.

6.) y=-2/3x+300

Step-by-step explanation:

some of these are part of the problem as well.

1.)  2x+3y=1,470  

3y=-2x+1,470

-2x+1,470/3

-2/3x + 490

y=-2/3x + 490

the y intercept is 490 and the slope is -2/3x

2.) First, I would find the point (0,490) and plot a point there. Then I would use our slope -2/3 to figure out what direction and what angle the line goes by counting 2 down and 3 to the right

3.) f(x)= -2/3x+490

The graph represents how many wraps could've been sold for each number of sandwich sales to keep the same profit of $1,470.  

5.) 2x+3y=1,593

3y=-2x+1,593

y=-2/3x+531

the profits are the same (slope) but the y intercept is higher then the original graph.

6.) (150, 200) (300, 100)

y intercept= 300

m= 100-200/300-150 = -100/150 = -2/3

y=-2/3x+300

this was a question from a while ago but I thought I would answer it anyways, hope its right and hope it helps you! <3

5 0
2 years ago
In a group of 10 ​kittens, 5 are female. Two kittens are chosen at random. ​a) Create a probability model for the number of male
olya-2409 [2.1K]

Answer:

(b) Expected number of male kitten E(x) = 1

(c) Standard deviation is ±\frac{2}{3}.

Step-by-step explanation:

Given that,

Number of kittens in a group are 10. Out of these 5 are female.

To find:- (a) create a probability model of male kitten chosen.

    So,  total number of kitten = 10

           number of female kitten = 5    

then, Number of male kitten = 10-5= 5

Now total number of ways to choosing two kittens from group of 10 = ^{10} C_{2}

                                                                                                                 = \frac{10!}{2!\times8!}

                                                                                                                 = 45

for choosing (i) No male P(x=0) = P(Two female) =  \frac{^{5} C_{2}}{45}

                                                                           = \frac{2}{9}

                     (ii) 1 male P(x=1) = P(1 male and 1 female) = \frac{^{5} C_{1}\times^{5} C_{1}}{45} =  \frac{25}{45} =\frac{5}{9}

                     (iii) 2 male P(x=2)= P(2 male) =\frac{^{5} C_{2}}{45} =  \frac{2}{9}

      x_{i}                             0                     1                      2

P(X=x_{i})                           \frac{2}{9}                      \frac{5}{9}                      \frac{2}{9}

(b) what is expected number of male kittens chosen ?

    Expected number of male kitten E(x) =  o\times \frac{2}{9} + 1\times \frac{5}{9} + 2\times\frac{2}{9}

                                                                  = 1

(c) what is standard deviation ?

                              \sigma(x) = \sqrt{ (E(x^{2} )-(Ex)^{2})

No,                          

                               Ex^{2} =o\times \frac{2}{9} + 1\times \frac{5}{9} + 4\times\frac{2}{9}

                                       = \frac{13}{9}

                               \sigma(x)=\sqrt{\frac{13}{9} - 1 }=\sqrt{\frac{4}{9} }  

                                       = ± \frac{2}{3}

                               

6 0
2 years ago
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