Answer:
There can be 14,040,000 different passwords
Step-by-step explanation:
Number of permutations to order 3 letters and 2 numbers (total 5)
(AAANN, AANNA,AANAN,...)
= 5! / (3! 2!)
= 120 / (6*2)
= 10
For each permutation, the three distinct (English) letters can be arranged in
26!/(26-3)! = 26!/23! = 26*25*24 = 15600 ways
For each permutation, the two distinct digits can be arranged in
10!/(10-2)! = 10!/8! = 10*9 = 90 ways.
So the total number of distinct passwords is the product of all three permutations,
N = 10 * 15600 * 90 = 14,040,000
Answer:
25
Step-by-step explanation:
172,000 is the answer I think
A- It will be smaller, because we're finding a part of a number, and it's no more than 100 percent.
B- It would be greater. It's more than 100 percent, which accounts for the whole value, and goes even more.
Hope this helps!
Answer:
Step-by-step explanation:
Mixed number Improper fraction
a) 1 + 1 + 1/3 = 
7/3
b) 1 + 1 + 1 + 5/8 = 
29/8
c) 1 + 1 + 1 +2/4 = 
14/4
