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sergij07 [2.7K]

3 years ago

14

1. Define "Conjugate radical binomials."

1 answer:

DerKrebs [107]3 years ago

6 0

Step-by-step explanation:

For a+b, it's a−b. A conjugate is a binomial where the second term is the opposite of the second term of another binomial. In other words, if I have the expression a+b, the conjugate of my expression is a−b. If I were to add the second terms of these two expressions, I would get 0.

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At what points does the curve r(t) = ti + (3t − t2)k intersect the paraboloid z = x2 + y2? (if an answer does not exist, enter d

tekilochka [14]

$\mathbf r(t)=x(t)\,\mathbf i+y(t)\,\mathbf j+z(t)\,\mathbf k=t\,\mathbf i+(3t-t^2)\,\mathbf k$

Along the curve $\mathbf r(t)$ , we have $y(t)=0$ , so the equation of the paraboloid reduces to

$z=x^2\iff3t-t^2=t^2\implies2t^2-3t=t(2t-3)=0\implies t=0\text{ and }t=\dfrac32$

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Eight chairs weigh 56 pounds. How much do 5 chairs weigh?

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The answer is 35 pounds because,
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3 years ago

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finlep [7]

Answer:

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Let f(x) = 3x - 7. What is f(1)?

Ipatiy [6.2K]

Answer:

no

negative 4 i think im dumb tho

Step-by-step explanation:

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3 years ago

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For what value(s) of k will the relation not be a function?

kolbaska11 [484]

Answer:

See below

Step-by-step explanation:

The relation is not a function when x -value is same but y- values are different.

#1

k^2 = 4k
k = 0, k = 4

#2

k^2 - 5k = k + 7
k^2 - 6k = 7
k^2 - 6k + 9 = 16
k - 3 = 4 ⇒ k = 7
k - 3 = -4 ⇒ k = -1

#3

k^3 - 5k^2 + 3k = -k
k^3 - 5k^2 + 4k = 0
k(k^2 - 5k + 4) = 0
k = 0, k = 1, k = 4

#4

|k + 1| + 2 = 8
|k + 1| = 6
k = 5, k = -7

8 0

3 years ago