2^5 ... 2 x 2 x 2 x 2 x 2
Answer:37.2 sec
Step-by-step explanation:
Given
Joel takes 81 sec for 14 mile long track
speed of joel
mi/min=10.37 mi/min
Jason takes 69 sec for 14 mi track
so jason speed is 
if both starts from same spot in opposite direction then

where x is distance covered by Joel
then x=6.44 miles
therefore time required

Answer:
y = - 16t² + 55.6t + 6
Step-by-step explanation:
Using y - y₀ = vt - 1/2gt² where g = 32 ft/s², and v the velocity of the football
So y = y₀ + vt - 1/2 × (32 ft/s²)t²
y = y₀ + vt - 16t² where y₀ = 6.5 ft
y = 6 + vt - 16t²
Now, when t = 3.5 s, that is the time the teammate catches the ball after the quarterback throws it, y = 5 ft. Substituting these into the equation, we have
5 = 6.5 + v(3.5 s) - 16(3.5 s)²
5 = 6.5 + 3.5v - 196
collecting like terms, we have
5 - 6.5 + 196 = 3.5v
194.5 = 3.5v
v = 194.5/3.5 = 55.57 ft/s ≅ 55.6 ft/s
So, substituting v into y, our quadratic model is
y = 6 + 55.6t - 16t²
re-arranging, we have
y = - 16t² + 55.6t + 6
Answer:
Mean: 1.5
Standard Deviation: 0.9
Step-by-step explanation:
2/3 of the pages have diagrams, and N is the number of pages Harlee reads to reach a page with a diagram. In order to find the mean, divide 1/(2/3) to get 1.5 as your mean, and then divide sqrt(1-(2/3))/2/3 to get .8660, which rounds to .9.
Answer: slope is 1
equation: 1x-2 or x-2
I hope this is good enough: