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den301095 [7]
2 years ago
12

Consider a parabola P that is congruent to y=x^2, opens upward, and has vertex (0,0). Find the equation of a new parabola that r

esults if P is reflected in the x-axis, and translated 1 unit to the left and 3 units up.
Mathematics
1 answer:
slega [8]2 years ago
7 0

9514 1404 393

Answer:

  y = -(x+1)^2 +3

Step-by-step explanation:

Translating f(x) left by 1 unit replaces x with x+1.

Translating f(x) up by 3 units replaces f(x) with f(x)+3.

Reflecting f(x) over the x-axis replaces f(x) with -f(x).

__

When y = x^2 is reflected over the x-axis, it becomes ...

  y = -x^2

When y = -x^2 is translated 1 unit left, it becomes ...

  y = -(x +1)^2

When y = -(x+1)^2 is translated 3 units up, it becomes ...

  y = -(x +1)^2 +3

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Answer:

Step-by-step explanation:

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julia-pushkina [17]

Answer:

y= 12

Step-by-step explanation:

2/3 y + 7 = 15

Subtract 7 from each side

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3 years ago
Convert the Cartesian equation (x 2 + y 2)2 = 4(x 2 - y 2) to a polar equation.
SashulF [63]

<u>ANSWER</u>

{r}^{2}  = 4  \cos2\theta

<u>EXPLANATION</u>

The Cartesian equation is

{( {x}^{2}  +  {y}^{2} )}^{2}  = 4( {x}^{2} -  {y}^{2}  )

We substitute

x = r \cos( \theta)

y = r \sin( \theta)

and

{x}^{2}  +  {y}^{2}  =  {r}^{2}

This implies that

{( {r}^{2} )}^{2}  = 4(( { r \cos\theta)  }^{2} -  {(r \sin\theta) }^{2}  )

Let us evaluate the exponents to get:

{r}^{4}  = 4({  {r}^{2} \cos^{2}\theta } -   {r}^{2}  \sin^{2}\theta)

Factor the RHS to get:

{r}^{4}  = 4{r}^{2} ({   \cos^{2}\theta } -   \sin^{2}\theta)

Divide through by r²

{r}^{2}  = 4 ({   \cos^{2}\theta } -   \sin^{2}\theta)

Apply the double angle identity

\cos^{2}\theta -\sin^{2}\theta=  \cos(2 \theta)

The polar equation then becomes:

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