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3 years ago

11

Anyone know how to check solution, please help if u do

1 answer:

Ivenika [448]3 years ago

3 0

Let's check your answer. To do this, you would simply plug your answer into the equation and see if it works.
5(y - 3) - 2 (3 - 2y) = 6
5(3 - 3) - 2(3 - 2 × 3) = 6

The equation works!

Y = 3

Great work!

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(6x - 12)/3 + 4 = 18/x

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3 years ago

X - (-20) = 5 _________________

tamaranim1 [39]

X - (-20) = 5

When you subtract a negative, change it to addition:

X + 20 = 5

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X = -15

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3 years ago

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-5x-18y=-28 and -10x+9y=-11 solve elimination

Dmitry [639]

Answer:

$\mathrm{The\:solutions\:to\:the\:system\:of\:equations\:are:}$

$x=2,\:y=1$

Step-by-step explanation:

Given the equations

$-5x-18y=-28$

$-10x+9y=-11$

solving the system of the equation by elimination method

$\begin{bmatrix}-5x-18y=-28\\ -10x+9y=-11\end{bmatrix}$

$\mathrm{Multiply\:}-5x-18y=-28\mathrm{\:by\:}2\:\mathrm{:}\:\quad \:-10x-36y=-56$

$\begin{bmatrix}-10x-36y=-56\\ -10x+9y=-11\end{bmatrix}$

$-10x+9y=-11$

$-$

$\underline{-10x-36y=-56}$

$45y=45$

$\begin{bmatrix}-10x-36y=-56\\ 45y=45\end{bmatrix}$

solve 45y=5 for y:

$45y=45$

$\frac{45y}{45}=\frac{45}{45}$

$y=1$

$\mathrm{For\:}-10x-36y=-56\mathrm{\:plug\:in\:}y=1$

solve $-10x-36\cdot \:1=-56$ for x:

$-10x-36\cdot \:1=-56$

$-10x-36=-56$

Add 36 to both sides

$-10x-36+36=-56+36$

$-10x=-20$

$\frac{-10x}{-10}=\frac{-20}{-10}$

$x=2$

$\mathrm{The\:solutions\:to\:the\:system\:of\:equations\:are:}$

$x=2,\:y=1$

5 0

3 years ago

X^2 - (x-y)^2 •y. If x = -5 and y = -8

ki77a [65]

Equation: x² - (x - y)² * y

Substitute values for x and y into equation.

-> (-5)² - ( (-5) - (-8) )² * (-8)
-> 25 - (-5 + 8)² * (-8)
-> 25 - (3)² * (-8)
-> 25 - 9 * (-8)
-> 25 - (-72)
-> 25 + 72
-> 97

3 0

3 years ago