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lianna [129]
3 years ago
7

Which criteria must be true to conclude that ABCD is a parallelogram?

Mathematics
1 answer:
SSSSS [86.1K]3 years ago
4 0

Answer:

AC⎯⎯⎯⎯⎯≅BD⎯⎯⎯⎯⎯

AC≅BD

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alekssr [168]
1. Yes, because y=kx. “Y” is equal to 4 × “x”, on every problem. y=4x
2. No, because on the first set of numbers 3 and 15 the equation is Y=5x. Then on the second set of numbers 4 and 17 the equation is Y=4.25x.
3. Yes, because Y=1.5x.
7 0
4 years ago
Does 36x+24=12(x+2+2x) , have no solution, one solution, many solutions?
Reika [66]

Answer:

No solution

Step-by-step explanation:

7 0
3 years ago
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Find the fourth term of the sequence given by the rule tn=4(2)^n-1
Andre45 [30]
Answer: Choice A) 32

-----------------------------------------------
-----------------------------------------------

Plug n = 4 into the formula

tn = 4(2)^(n-1)
t4 = 4(2)^(4-1) ... every n is replaced with 4
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8 0
4 years ago
Jill has a collection of bugs. Her collection contains butterflies and tarantulas. She has 47 bugs and counts 320 total legs. (N
prisoha [69]

Answer:

The solution to this system of equations is:

  • B = 28
  • T = 19

Step-by-step explanation:

We are given that Jill has 47 bugs and counts a total 320 legs.

We can concur that by adding the total number of butterflies and the total number of tarantulas, we will get 47 bugs.

\text{tarantulas + butterflies} = 47

We are also told that T is tarantulas and B is butterflies.

T + B = 47

Then, we also know that butterflies have 6 legs and tarantulas have 8 legs. So, for every tarantula, we get a multiple of 8 and for butterflies, we get a multiple of 6. This gives us a new equation:

6B + 8T = 320

Now, we can set up a system of equation.

\displaystyle \left \{ {{B + T = 47} \atop {6B + 8T = 320}} \right.

Using the first equation, we can solve for B.

\displaystyle B + T = 47\\\\B + T - T = 47 - T\\\\B = 47 - T

Then, we can substitute this value of B into the second equation and solve for T.

\displaystyle 6(47-T)+8T=320\\\\282 - 6T + 8T = 320\\\\282 + 2T = 320\\\\2T + 282 = 320\\\\2T + 282 - 282 = 320 -282\\\\2T = 38\\\\\frac{2T}{2}=\frac{38}{2}\\\\T = 19

Finally, we can substitute this value of T into the first equation to solve for B.

B + 19 = 47\\\\B + 19 - 19 = 47 - 19\\\\B = 28

Therefore, the solution to this system of equations is:

  • B = 28
  • T = 19
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3 years ago
Đạo hàm √((6t-4t²) ²+64)
Elza [17]

Answer:

(6 - 8t)(6t - 4t²) / ((6t - 4t²)² + 64)⁰‧⁵

5 0
3 years ago
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