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madreJ [45]
3 years ago
14

What are the solutions of the quadratic equation 4x^2-8x-12=0

Mathematics
1 answer:
Wewaii [24]3 years ago
6 0

Answer:

<h3>          x₁ = -1,   x₂ = 3</h3>

Step-by-step explanation:

4x^2-8x-12=0\\{}\qquad\qquad^{\div4\qquad\div4}\\x^2-2x-3=0\\\\x^2+x-3x-3=0\\\\x(x+1)-3(x+1)=0\\\\(x+1)(x-3)=0\\\\x+1=0\quad\vee\quad x-3=0\\\\x=-1\quad\vee\quad x=3

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