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3 years ago

What are the solutions of the quadratic equation 4x^2-8x-12=0

Mathematics

1 answer:

Wewaii [24]3 years ago

6 0

Answer:

Step-by-step explanation:

$4x^2-8x-12=0\\{}\qquad\qquad^{\div4\qquad\div4}\\x^2-2x-3=0\\\\x^2+x-3x-3=0\\\\x(x+1)-3(x+1)=0\\\\(x+1)(x-3)=0\\\\x+1=0\quad\vee\quad x-3=0\\\\x=-1\quad\vee\quad x=3$

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Step-by-step explanation:

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Agata [3.3K]

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Step-by-step explanation:

I already explained it on another problem but I'll show the equation again.

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