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Sonja [21]
3 years ago
11

There are currently 20 members in the school's Ski Club and the dues are $10 per member. To encourage the recruiting of new memb

ers, the club treasurer suggests that for each new member recruited, the dues for all members will be reduced by 10 cents. Write an equation in standard form to represent this situation.
Mathematics
1 answer:
guajiro [1.7K]3 years ago
8 0

Answer:

f(n)=-0.10n^2+8n+200

Step-by-step explanation:

Let n represent number of new members and f(n) represent membership money.

We have been given that there are currently 20 members in the school's Ski Club. So when n new members join, the total number of members would be 20+n.

Since for each new member recruited the dues for all members will be reduced by 10 cents, so new dues would be 10-0.10n.

The membership money would be number of total members times dues as:

f(n)=(20+n)(10-0.10n)

Since we need our equation in standard form, so we will use FOIL to expand our equation as:

f(n)=20(10)-20(0.10n)+n(10)-n(0.10n)

f(n)=200-2n+10n-0.10n^2

f(n)=200+8n-0.10n^2

f(n)=-0.10n^2+8n+200

Therefore, our required equation would be f(n)=-0.10n^2+8n+200.

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(9.885-0.365)÷1.7+4.4

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This season, Lisa's lacrosse team has won $\frac 23 of their home games (games played at Lisa's school), but just $\frac 25 of t
juin [17]

Answer:

Lisa's team have played 24 home games and 25 away games.

Step-by-step explanation:

Given:

Let x represents games played at home.

also y represent games played away.

Total number of games played = 49

∴ x+y=49 \ \ \ \  equation \ 1

Now according to given data:

Number of home games won = \frac{2}{3}

Number of away game won = \frac{2}{5}

Total games won =26

Hence

\frac{2}{3}x+\frac{2}{5}y=26\\\\\frac{2\times 5}{3\times 5}x+\frac{2\times 3}{5\times 5}y=26\\\\\frac{10}{15}x+\frac{6}{15}y=26\\\\\frac{10x+6y}{15}=26\\\\10x+6y= 26\times 15\\10x+6y = 390\\2(5x+3y)=390\\5x+3y=\frac{390}{5}\\\\5x+3y=195 \ \ \ \ equation \ 2\\

Now multiplying equation 1 by 3 we get,

3(x+y)=3\times49\\3x+3y=147 \ \ \ \ \ equation \ 3\\

Now Subtracting equation 2 by equation 3 we get,

(5x+3y=195)-(3x+3y=147)\\2x=48\\x= \frac{48}{2}=24

Substituting value of x in equation 1 we get.

x+y=49\\24+y=49\\y=49-24=25

Hence Lisa's team have played 24 home games and 25 away games.

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3 years ago
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