Produce it to Perfect square trinomials p²+4pg

marcela tardo dos horas menos que roberto en recorrer una distancia en bicicleta, SI el producto de los dos tiempos es de 48 hor

Kaylis [27]

Answer:

Marcela tardó 6 horas y Roberto tardó 8 horas.

Step-by-step explanation:

Dado que Marcela tardó dos horas menos que Roberto en recorrer una distancia en bicicleta, y sabiendo que el producto de los dos tiempos es de 48 horas, para determinar cuánto tardó cada uno se debe realizar el siguiente cálculo:

M = X

R = X + 2

X x (X + 2) = 48

8 x 6 = 48

Por lo tanto, Marcela tardó 6 horas y Roberto tardó 8 horas.

8 0

3 years ago

Which statements about the function are true? Select two

iogann1982 [59]

Answer:

The vertex of the function is at (1,-25)

Step-by-step explanation:

I think your question missed key information, allow me to add in and hope it will fit the orginal one.

Part of the graph of the function f(x) = (x + 4)(x-6) is shown below.

Which statements about the function are true? Select two

options.

The vertex of the function is at (1,-25).

The vertex of the function is at (1,-24).

The graph is increasing only on the interval -4< x < 6.

The graph is positive only on one interval, where x <-4.

The graph is negative on the entire interval

My answer:

Given the factored form of the function:

f(x) = (x + 4)(x-6)

<=> f(x) = $x^{2} - 2x -24$

We will convert to vertex form

<=> f(x) = ( $x^{2} - 2x +1$ ) - 25

<=> f(x) = $(x-1)^{2} -25$

=> the vertex of the function is: (1,-25)

We choose: a. The vertex of the function is at (1,-25)

Let analyse other possible answers:

c. The graph is increasing only on the interval -4< x < 6.

Because the parameter a =1 so the graph open up all over its domain and the vertex is the lowest point.

So the graph is increasing in the domain (1, +∞)

=> C is wrong

d. The graph is positive only on one interval, where x <-4

Wrong, The graph is positive only on one interval, where x > 6

e. The graph is negative on the entire interval

Wrong, The graph is negative only on one interval, where -4< x < 6.

7 0

4 years ago

In engineering, the modulus of elasticity is a way to measure how much an object deforms along an axis when opposing forces are

Allushta [10]

Step-by-step explanation:

Consider an engineering material of initial length Lo, Area (A), Modulus of elasticity (E) and applied a force P due to which change in the length of the material is δ2 from it’s original length (Lo)

Initial length of the material is Lo. Hence, at time t = 0 when no force applied on the material the length of the material will not change (i.e., at time t=0, δ1 = 0)

Modulus of elasticity of the material:

$E=\frac{P \cdot L_{o}}{A\left[\delta_{2}-\delta_{1}\right]}$