The temperature was -14°F at 8 a.m.
At noon is was 10 degrees warmer - the temperature increase was 10°F
-14°F + 10°F = -4°F
The tempertaure increase between noon and 4 p.m. was twice the previous increase in temperature, which was 10°F.
10°F x 2 = 20°F
We want to know the temperature at 4 p.m. so we just add it up to the previous result.
-4°F + 20°F = 16°F
16°F is the correct answer
Step-by-step explanation:
we have y intercept -10
and slope 3
we know the equation of line in slope -intercept form
y=mx+b
where m is slope and b is y-intercept
so the final equation would be
y=3x-10
Sqr (x2 - x1)^2 + (y2 - y1)^2
Sqr (-4-0)^2 + (2+5)^2
Sqr (16) + 49 = sqr 65
I got around 8.
(I might did something wrong, idk)
Answer:
Using reflexive property (for side), and the transversals of the parallel lines, we can prove the two triangles are congruent.
Step-by-step explanation:
- Since AB and DC are parallel and AC is intersecting in the middle, you can make out two pairs of alternate interior angles<em>.</em> These angle pairs are congruent because of the alternate interior angles theorem. The two pairs of congruent angles are: ∠DAC ≅ ∠BCA, and ∠BAC ≅ ∠DCA.
- With the reflexive property, we know side AC ≅ AC.
- Using Angle-Side-Angle theorem, we can prove ΔABC ≅ ΔCDA.
+ √6 = √9
The first step is to get
by itself. We can do this by subtracting
from each side, and simplifying 
= 3 - 
Now we square both sides
5x = (3 -
)²
Using the formula (a - b)² = a² -2ab + b², (3 -
)² = 15 - 6
5x = 15 - 6
x = 