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3 years ago

Multiply 11 1/9 * 4 2/7 to the simplest form

Mathematics

1 answer:

andreev551 [17]3 years ago

8 0

Answer:

= 47 13/21?

Step-by-step explanation:

i think...

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DECK is a parallelogram with m∠1 = 20°, m∠(<img src="https://tex.z-dn.net/?f=x%5E%7B2%7D" id="TexFormula1" title="x^{2}" alt="x^

maw [93]

9514 1404 393

Answer:

m∠2 = 16° or 25°

Step-by-step explanation:

The sum of angles 1 and 2 is congruent to angle CED.

20° +(x^2)° = (9x)°

x^2 -9x +20 = 0 . . . . . divide by °, put in standard form

(x -5)(x -4) = 0 . . . . . . . factor

x = 5 or 4

m∠2 = (x^2)° = (5^2)° or (4^2)°

m∠2 = 16° or 25°

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3 years ago

A study conducted by a local university found that 25 percent of college freshmen support increased spending on environmental is

AnnyKZ [126]

Answer:

13.18% or 0.1318

Step-by-step explanation:

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4 years ago

What is the sum of

creativ13 [48]

Answer:

Step-by-step explanation:

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3 years ago

Sarah is carrying out a series of experiments which involve using mcreasing amounts of a chemical. In the

Marianna [84]

Sarah is carrying out a series of experiments which involve using increasing amounts of a chemical. In the first experiment she uses 6g of the chemical and in the second experiment she uses 7.8 g of the chemical

(i)Given that the amounts of the chemical used form an arithmetic progression find the total amount of chemical used in the first 30 experiments

(ii)Instead it is given that the amounts of the chemical used for a geometric progression. Sarah has a total of 1800 g of the chemical available. Show that the greatest number of experiments possible satisfies the inequality: $1.3^N \leq 91$ and use logarithms to calculate the value of N.

Answer:

(a)963 grams

(b)N=17

Step-by-step explanation:

(a)

In the first experiment, Sarah uses 6g of the chemical

In the second experiment, Sarah uses 7.8g of the chemical

If this forms an arithmetic progression:

First term, a =6g

Common difference. d= 7.8 -6 =1.8 g

Therefore:

Total Amount of chemical used in the first 30 experiments

$S_n=\dfrac{n}{2}[2a+(n-1)d] \\S_{30}=\dfrac{30}{2}[2*6+(30-1)1.8] \\=15[12+29*1.8]\\=15[12+52.2]\\=15*64.2\\=963$ grams$

Sarah uses 963 grams in the first 30 experiments.

(b) If the increase is geometric

First Term, a=6g

Common ratio, r =7.8/6 =1.3

Sarah has a total of 1800 g

Therefore:

Sum of a geometric sequence

$S_n=\dfrac{a(r^N-1)}{r-1} \\1800=\dfrac{6(1.3^N-1)}{1.3-1} \\1800=\dfrac{6(1.3^N-1)}{0.3}\\$Cross multiply\\1800*0.3=6(1.3^N-1)\\6(1.3^N-1)=540\\1.3^N-1=540\div 6\\1.3^N-1=90\\1.3^N=90+1\\1.3^N=91$