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3 years ago

This too? thank you so much

Mathematics

2 answers:

mars1129 [50]3 years ago

4 0

Answer:

The hypotenuse is the longest side of the triangle.

You need to add 37+12.

That is 49.

That is not in the menu.

dezoksy [38]3 years ago

4 0

Answer:

sfdsdsgdfdsgsfdgdgfd thats the answer how do you people not even know a single answer 0-o

Step-by-step explanation:

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Subtract 3x squared +7x-4 from 8x squared-6+2 your answer should be polynomial in standard form

aleksley [76]

Answer:

5x² - 13x + 6

Step-by-step explanation:

8x² - 6x + 2 - (3x² +7x -4)

Simplify the expression:

8x² - 6x + 2 - 3x² -7x + 4

Combine like terms:

5x² - 13x + 6

6 0

3 years ago

(-23, – 8) and (722 -8)

Andre45 [30]

-51 and 714

Step-by-step explanation:

-23-38=-51

722-8=714

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3 years ago

How much is 4 raised to 4?

Over [174]

Answer:

4 raised to 4 is 256

Step-by-step explanation:

5 0

2 years ago

Read 2 more answers

Help Please i beg you

Amiraneli [1.4K]

Answer:

y = 7x - 2

Step-by-step explanation:

m = slope

b = y int

Have a good day!!!

6 0

2 years ago

Read 2 more answers

If sin θ =8/9. Find cot θ.

olga nikolaevna [1]

Step-by-step explanation:

✧ $\underline{ \underline{ \large{ \tt{G\: I \: V \: E\: N}}} }:$

$\large{ \tt{sin \: \theta = \frac{8}{9}}}$ Here , Perpendicular ( p ) = 8 & hypotenuse ( h ) = 9

♨ $\underline{ \underline{ \large{ \tt{ T \: O \: \: F \: I\: N\: D}}}} :$

$\large{ \tt{cot \: \theta}}$

♨ $\underline{ \underline{ \large{ \tt{S \: O \: L\: U \: T\: I\: O \: N}}}} :$

First, Find the base ( b ) using Pythagoras theorem :

☪ $\boxed{ \bf{ {h}^{2} = {p}^{2} + {b}^{2} }}$

~Plug all the known values and then simplify!

⇾ $\large{ \bf{ {9}^{2} = {8}^{2} + {b}^{2} }}$

⇾ $\large{ \bf{81 = 64 + {b}^{2} }}$

⇾ $\large{ \bf{64 + {b}^{2} = 81}}$

⇾ $\large{ \bf{ {b}^{2} = 81 - 64}}$

⇾ $\large{ \bf{ {b}^{2} = 17}}$

⇾ $\large{ \bf{b = \sqrt{17}}}$

Now , Find the value of cot θ

We know ;

⟿ $\large{ \bf{cot \theta = \frac{b}{p} = \boxed{ \bf{ \frac{ \sqrt{17} }{8}}}}}$

⤷ $\boxed{ \boxed{ \underline{ \large{ \tt{Our \: Final \: Answer : { \tt{ \frac{ \sqrt{17} }{8} }}}}}}}$

( Correct me if I'm wrong )

Hope I helped ! ♡

Have a wonderful day / night ! ツ

☄ Let me know if you have any questions regarding my answer !

$\underline{ \underline{ \mathfrak{Carry \: On \: Learning}}}$ !! ✎

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7 0

2 years ago