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Ede4ka [16]
3 years ago
5

If the measure is 3= 122, then the m6= ?

Mathematics
1 answer:
Vladimir [108]3 years ago
7 0

Yo sup??

m3 and m6 for a supplementary pair therefore

m3+m6=180

122+m6=180

m6=58

Hope this helps

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Find the slope of the line containing the two points (1,-1) and (-5,-3)
Strike441 [17]
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answer
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4 0
3 years ago
Write the equation of a polynomial of degree 3, with zeros 1, 2 and -1 where f(0)=2
drek231 [11]

<u>Answer:</u>

The equation of a polynomial of degree 3, with zeros 1, 2 and -1 is x^{3}-2 x^{2}-x+2=0

<u>Solution:</u>

Given, the polynomial has degree 3 and roots as 1, 2, and -1. And f(0) = 2.

We have to find the equation of the above polynomial.

We know that, general equation of 3rd degree polynomial is  

F(x)=x^{3}-(a+b+c) x^{2}+(a b+b c+a c) x-a b c=0

where a, b, c are roots of the polynomial.

Here in our problem, a = 1, b = 2, c = -1.

Substitute the above values in f(x)

F(x)=x^{3}-(1+2+(-1)) x^{2}+(1 \times 2+2(-1)+1(-1)) x-1 \times 2 \times(-1)=0

\begin{array}{l}{\rightarrow x^{3}-(3-1) x^{2}+(2-2-1) x-(-2)=0} \\ {\rightarrow x^{3}-(2) x^{2}+(-1) x-(-2)=0} \\ {\rightarrow x^{3}-2 x^{2}-x+2=0}\end{array}

So, the equation is x^{3}-2 x^{2}-x+2=0

Let us put x = 0 in f(x) to check whether our answer is correct or not.

\mathrm{F}(0) \rightarrow 0^{3}-2(0)^{2}-0+2=2

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3 0
3 years ago
The graphs of quadrilateral LMNO and its image are shown below.
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Hello!

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(-5,-4)⇒(0,3) was translate up 7 units and translated right 5 units.

I hope this helps!
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Irina-Kira [14]
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