Answer:
a) The cost of ribeye steak dinners is $ 16.96.
b) The cost of grilled salmon dinners is $ 23.37.
Explanation:
Let the cost for ribeye steak dinners be m and cost for grilled salmon dinners be n.
A waitress sold 10 ribeye steak dinners and 18 grilled salmon dinners, totaling $590.39 on a particular day.
So, we have
10 m + 18 n = 590.39 -------equation 1
Another day she sold 22 ribeye steak dinners and 9 grilled salmon dinners, totaling $583.49
So, we have
22 m + 9 n = 583.49 -------equation 2
equation 2 x 2
44 m + 18 n = 1166.98 -------equation 3
equation 3 - equation 1
44 m + 18 n - ( 10 m + 18 n ) = 1166.98 - 590.39
m = 16.96 $
Substituting in equation 1
22 x 16.96 + 9 n = 583.49
n = 23.37 $
a) The cost of ribeye steak dinners is $ 16.96.
b) The cost of grilled salmon dinners is $ 23.37.
42.96 I think
I’m very sorry if I’m wrong but I’m 90 sure I’m right
Answer:
y = -4x + 29
Step-by-step explanation:
-3 = -4(8) + b
-3 = -32+b
29=b
The greatest possible number of club members is 7
<em><u>Solution:</u></em>
Given that, local readers’ club has a set of 49 hardback books and a set of 21 paperbacks
Each set can be divided equally among the club members
To find the greatest possible number of club members, we have to find the greatest common factor of 49 and 21
The greatest number that is a factor of two (or more) other numbers.
When we find all the factors of two or more numbers, and some factors are the same ("common"), then the largest of those common factors is the Greatest Common Factor.
<em><u>Greatest common factor of 49 and 21:</u></em>
The factors of 21 are: 1, 3, 7, 21
The factors of 49 are: 1, 7, 49
Then the greatest common factor is 7
Thus, the greatest possible number of club members is 7
