Answer:

Step-by-step explanation:
Let 
![m=(y^3)^{\frac{1}{2}}\\\\m=y^{3\times \frac{1}{2}}\ \ \ \ \ \ \ \ \ [as\ (x^a)^b=x^{ab}]\\\\m=y^{\frac{3}{2}](https://tex.z-dn.net/?f=m%3D%28y%5E3%29%5E%7B%5Cfrac%7B1%7D%7B2%7D%7D%5C%5C%5C%5Cm%3Dy%5E%7B3%5Ctimes%20%5Cfrac%7B1%7D%7B2%7D%7D%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5Bas%5C%20%28x%5Ea%29%5Eb%3Dx%5E%7Bab%7D%5D%5C%5C%5C%5Cm%3Dy%5E%7B%5Cfrac%7B3%7D%7B2%7D)
Answer:
10 10/11
Step-by-step explanation:
Ella has 0.5 lbs of sugar. 75% syrup
Percent of mass = 
Let the mass of solution is x
Given mass of solute = 0.5
percent of mass = 75
75 = 
75x = 0.5 * 100
75 x = 50
x = 0.67
Mass of solution = 0.67
Mass of water = mass of solution - mass of solute (sugar)
= 0.67 - 0.5 = 0.17
So 0.17lb of water is added with 0.5lb of sugar to get 0.67lb of solution.