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Masja [62]
3 years ago
7

The point (5, 7) is reflected over the x-axis. What are the coordinates of its image?

Mathematics
2 answers:
timama [110]3 years ago
7 0
If it is reflected over the x-axis that would have to be (5,-7). :P
s344n2d4d5 [400]3 years ago
7 0
The correct answer is (5,-7) Hope that helps!
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Find the equation of the line that<br> is parallel to y = 4x + 1 and<br> contains the point (1, 1).
n200080 [17]

Answer:

y=4x+1

answer= y=4x

Step-by-step explanation:

y=4x+1

1=4(1)+1

1=5

4 0
3 years ago
Read 2 more answers
Factor the expression.
g100num [7]

Answer:

(x + 1) (3 x^2 + 1)

Step-by-step explanation:

Factor the following:

3 x^3 + 3 x^2 + x + 1

Factor terms by grouping. 3 x^3 + 3 x^2 + x + 1 = (3 x^3 + 3 x^2) + (x + 1) = 3 x^2 (x + 1) + (x + 1):

3 x^2 (x + 1) + (x + 1)

Factor x + 1 from 3 x^2 (x + 1) + (x + 1):

Answer:  (x + 1) (3 x^2 + 1)

6 0
4 years ago
Jose brought 9 pounds of rice for $4. How many pounds of rice did he get per dollar?​
NikAS [45]

Answer:

1.5 pound ever dollar

Step-by-step explanation:

just calculate

7 0
3 years ago
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What number is 16% of 44 rounded to the nearest tenth show the work also and thxs
OLEGan [10]
SOLUTION:

16% of 44 = 44 × 16% OR 44 × 16 / 100 OR 44 × 0.16

16% of 44 = 7.04

16% of 44 = 7.0 ( rounded to the nearest tenth )

Hope this helps! :)
Have a lovely day! <3
7 0
3 years ago
Solve the quadratic equation by completing the square.
Step2247 [10]

Answer:

x1, x2 = 4.74 , -2.74

Step-by-step explanation:

To find the roots of a quadratic function we have to use the bhaskara formula

ax^2 + bx + c

x^2 - 2x - 13

a = 1     b = -2    c = -13

x1 = (-b + √ b^2 - 4ac)/2a

x2 =(-b - √ b^2 - 4ac)/2a

x1 = (2 + √ (2^2 - 4 * 1 * (-13)))/2 * 1

x1 = (2 + √ (4 + 52)) / 2

x1 = (2 + √ 56 ) / 2

x1 = (2 + 7.48) / 2

x1 = 9.48 / 2

x1 = 4.74

x2 = (2 - √ (2^2 - 4 * 1 * (-13)))/2 * 1

x2 = (2 - √ (4 + 52)) / 2

x2 = (2 - √ 56 ) / 2

x2 = (2 - 7.48) / 2

x2 = -5.48 / 2

x2 = -2.74

6 0
3 years ago
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