Answer:
The independent quantity in the situation is the length of the diameter.
Step-by-step explanation:
Consider a relationship between two variables.
Of the two variables one variable is dependent upon the other.
Dependent variables are those variables that are under study, i.e. they are being observed for any changes when the other variable values are changed.
Independent variables are the variables that are being altered to see a proportionate change in the dependent variable.
In this case, it is provided that Grissom knows there is a relationship between the volume of the sphere and the length of its diameter.
With every sphere that Grissom draws, the volume of the sphere changes according to its diameter length.
That is the volume of the sphere depends upon the length of its diameter.
Thus, the independent quantity in the situation is the length of the diameter.
To solve this problem, we will subtract the volume of the cylinder from the volume of the rectangular prism.
The volume of a cylinder is: pi*r^2*h
Substitute 2 in for r and 6 in for h. If the diameter is 4, then the radius is 2.
pi*2^2*6
pi*4*6
pi*24
=75.4 ft^2
The volume of the rectangular prism is: l*w*h.
Substitute 6 in for l, w and h, since all edges are equal.
6*6*6
36*6
=216 ft^2
Subtract 75.4 from 216
216-75.4=140.6
There is 140.6 cubic feet of concrete left in the block.
Answer:
x = 3
Step-by-step explanation:
We are told that the length of a side of the square is x.
Now, perimeter of square = 4 × side length
Perimeter of square = 4x
Also,we are told that the triangle is equilateral and a side is (x + 1).
Thus, perimeter of triangle = 3(x + 1)
Since we are told that the perimeter of the square is equal to that of the equilateral triangle. Thus;
4x = 3(x + 1)
4x = 3x + 3
Subtract 3x from both sides to get;
4x - 3x = 3
x = 3
To compare both, we find the volume of both cubes as follows:
V of cube A = 10 g / 10 g/cm^3 = 1 cm^3
V of cube B = 10 g / 0.37 g/cm^3 = 27 cm^3
I think the correct answer from the choices listed above is option D. Each edge of cube b is three times larger than cube. Hope this helps. Have a nice day.
Answer:
The length of river frontage for each lot are 96.55 ft. 98.85 ft, 101.15 ft and 103.45 ft.
Step-by-step explanation:
See the attached diagram.
The river frontage of 400 ft will be divided into 84 : 86 : 88 : 90 for each lot as AP, BQ, CR, DS and ET all are parallel.
Therefore, PQ : QR : RS : ST = 84 : 86 : 88 : 90 = 42 : 43 : 44 : 45
Let, PQ = 42x, QR = 43x, RS = 44x and ST = 45x
So, (42x + 43x + 44x + 45x) = 400
⇒ 175x = 400
⇒ x = 2.2988.
So, PQ = 42x = 96.55 ft.
QR = 43x = 98.85 ft.
RS = 44x = 101.15 ft and
ST = 45x = 103.45 ft
(Answer)
