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Scorpion4ik [409]
2 years ago
8

PLEASE HELP EMERGENCY

Mathematics
2 answers:
makvit [3.9K]2 years ago
6 0

Answer:

he because the Spence or bentualy

Troyanec [42]2 years ago
5 0
He because Spence butualy
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Solve for r.<br><br> r - 4.5 ≤ 11
erma4kov [3.2K]

Answer:

The answer is r < or equal to 15.5.

Step-by-step explanation:

3 0
2 years ago
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Divide 4/5 by 2/3.<br> a. 8/15b. 5/6c. 1 1/5d. 1 7/8
Ivan
4/5÷2/3=x
4/5×3/2=x
   12/10=x 
    1 1/5=x
5 0
2 years ago
The sample consisted of 50 night students, with a sample mean GPA of 3.02 and a standard deviation of 0.08, and 25 day students,
bulgar [2K]

Answer: The test statistic is t= -0.90.

Step-by-step explanation:

Since we have given that

n₁ = 50

n₂ = 25

\bar{x_1}=3.02\\\\\bar{x_2}=3.04\\\\\sigma_1=0.08\\\\\sigma_2=0.06

So, s would be

s=\sqrt{\dfrac{n_1\sigma_1^2+n_2\sigma_2^2}{n_1+n_2-2}}\\\\s=\sqrt{\dfrac{50\times 0.08^2+25\times 0.06^2}{50+25-2}}\\\\s=0.075

So, the value of test statistic would be

t=\dfrac{\bar{x_1}-\bar{x_2}}{s(\dfrac{1}{n_1}+\dfrac{1}{n_2})}\\t=\dfrac{3.02-3.04}{0.074(\dfrac{1}{50}+\dfrac{1}{25})}\\\\t=\dfrac{-0.04}{0.074(0.02+0.04)}\\\\t=\dfrac{-0.04}{0.044}\\\\t=-0.90

Hence, the test statistic is t= -0.90.

7 0
3 years ago
Each bag juwad picked holds 15 apples. How many apples did he pick in two weeks? write an expression to represent this problem.
MAVERICK [17]
The questions does not make sense
6 0
2 years ago
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Haley works at a candy store. There are 10 types of bulk candy. Find the probability that one type of candy will be chosen more
DIA [1.3K]

Answer:

Probability that one type of candy will be chosen more than once in 10 trials = 0.2639

Step-by-step explanation:

This is a binomial experiment because

- A binomial experiment is one in which the probability of success doesn't change with every run or number of trials.

- It usually consists of a number of runs/trials with only two possible outcomes, a success or a failure. (10 trials, with the outcome of each trial being that we get the required candy or not)

- The outcome of each trial/run of a binomial experiment is independent of one another.

Binomial distribution function is represented by

P(X = x) = ⁿCₓ pˣ qⁿ⁻ˣ

n = total number of sample spaces = 10 trials

x = Number of successes required = number of times we want to pick a particular brand of candy = more than once, that is > 1

p = probability of success = probability of picking a particular brand of candy from a bulk with 10 different types of candies = (1/10) = 0.10

q = probability of failure = Probability of not picking our wanted candy = 1 - p = 1 - 0.1 = 0.90

P(X > 1) = 1 - P(X ≤ 1)

P(X ≤ 1) = P(X = 0) + P(X = 1)

P(X = 0) = ¹⁰C₀ (0.10)⁰ (0.90)¹⁰⁻⁰ = 0.3486784401

P(X = 1) = ¹⁰C₁ (0.10)¹ (0.90)¹⁰⁻¹ = 0.387420489

P(X ≤ 1) = 0.3486784401 + 0.387420489 = 0.7360989291

P(X > 1) = 1 - 0.7360989291 = 0.2639010709 = 0.2639

Hope this Helps!!!

5 0
3 years ago
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