Home to 1st base = 90 ft
1st base to 2nd base = 90 ft
2nd base to 3rd base = 90 ft
3rd base to home = 90 ft
so we have a total of : (90 * 4) = 360 ft
there are 3 ft in 1 yd....
so in 360 ft, there are : 360/3 = 120 yds <==
or u could just figure it between each base....90 ft = (90/3) = 30 yds per base...and u have 4 bases....so that (4 * 30) = 120 yds
Answer:
- <u><em>About 0.22</em></u>
Explanation:
There are two sets:
- Set W of incoming seniors who took AP World History, and
- Set E of incoming seniors who took AP European History
And there is a subset, which is the intersection of those two sets:
- Subset W ∩ E of senior students who took both.
The incoming seniors who are allowed to enroll in AP U.S. History, call them the subset S, is the set of those students that belong to W or E or both W ∩E.
By property of sets:
- S = W + E - W∩E = 175 + 36 - 33 = 178
Then, 178 out of 825 incoming seniors took one or both courses, and the desired probability of a randomly selected incoming senior is allowed to enroll in AP U.S. History is:
Answer=Order of operations
The order of operations (which we use PEMDAS to help us remember) tells you which operation to do first.
