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2 years ago

a circled circumference is approximately 44cm

Mathematics

1 answer:

Sindrei [870]2 years ago

4 0

Answer:

1. The circle’s radius is approximately 14 cm.

2. The circle’s radius is approximately 7 cm.

3. The circle’s area is approximately 154 cm2

Question:a circled circumference is approximately 44cm

Complete each statement using one of these values : 7,11,14,22,88,138,154,196,380,616, Answers without letters: 1. 14cm 2. 7cm 3. 154 cm2

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.A retailer sold two articles at same price. He sold the first one at 10% profit and the

IRISSAK [1]

Step-by-step explanation:

so let's assume they both sold for 100 each the first article sold for 10% laws there by cost of article is 111.11 rounded the second article made 25% profit so cost must be 80 total cost is 8.89 or 5% profit I'm so sorry if im wrong

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2 years ago

MATH HELP PLEASE!!! USA TESTPREP!!

MaRussiya [10]

Answer:

B.) -3

Step-by-step explanation:

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2 years ago

Read 2 more answers

For f(x)=4sin(x2) between x=0 and x=3, find the coordinates of all intercepts, critical points, and inflection points to two dec

telo118 [61]

Answer:

Intercepts:

x = 0, y = 0

x = 1.77, y = 0

x = 2.51, y = 0

Critical points:

x = 1.25, y = 4

x = 2.17 , y = -4

x = 2.8, y = 4

Inflection points:

x = 0.81, y = 2.44

x = 1.81, y = -0.54

x = 2.52, y = 0.27

Step-by-step explanation:

We can find the intercept by setting f(x) = 0

$4sin(x^2) = 0$

$sin(x^2) = 0$

$x^2 = n\pi$ where n = 0, 1, 2,3, 4, 5,...

$x = \sqrt(n\pi)$

Since we are restricting x between 0 and 3 we can stop at n = 2

So the function f(x) intercepts at y = 0 and x:

x = 0

x = 1.77

x = 2.51

The critical points occur at the first derivative = 0

$f^{'}(x) = 4cos(x^2)2x = 8xcos(x^2) = 0$

$xcos(x^2) = 0$

$x = 0$ or

$cos(x^2) = 0$

$x^2 = \frac{\pi}{2} + n\pi$ where n = 0, 1, 2, 3

$x = \sqrt{\pi(n+1/2)}$

Since we are restricting x between 0 and 3 we can stop at n = 2

So our critical points are at

x = 1.25, $y = f(1.25) = 4sin(1.25^2) = 4$

x = 2.17 , $y = f(2.17) = 4sin(2.17^2) = -4$

x = 2.8, $y = f(2.8) = 4sin(2.8^2) = 4$

For the inflection point, we can take the 2nd derivative and set it to 0

$f^[''}(x) = 8(cos(x^2) - xsin(x^2)2x) = 8cos(x^2) - 16x^2sin(x^2) = 0$

$cos(x^2) = 2x^2sin(x^2)$

$tan(x^2) = \frac{1}{2x^2}$

We can solve this numerically to get the inflection points are at

x = 0.81, $y = f(0.81) = 4sin(0.81^2) = 2.44$

x = 1.81, $y = f(1.81) = 4sin(1.81^2) = -0.54$

x = 2.52, $y = f(2.52) = 4sin(2.52^2) = 0.27$

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2 years ago

To show that polygon ABCDE is congruent to polygon FGHIJ, a must be used to make the two polygons coincide. A sequence of two tr

Sati [7]

Hello.

The minimum number of rigid transformations required to show that polygon ABCDE is congruent to polygon FGHIJ is 2 (translation and rotation).

A rotation translation must be used to make the two polygons coincide.

A sequence of transformations of polygon ABCDE such that ABCDE does not coincide with polygon FGHIJ is a translation 2 units down and a 90° counterclockwise rotation about point D

Have a nice day

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3 years ago

Read 2 more answers

What is -3 - 9n= 42 I can’t be negative

maw [93]

If you were to correctly simplify this equation, the answer would be a negative.

The answer is: n = -5

Here's how I got my answer:

Step 1: Add 3 to both sides. Which leaves us with $-9n=42+3$