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Angelina_Jolie [31]
3 years ago
8

Find the nth term for the sequence 30 27 24 21

Mathematics
2 answers:
Nastasia [14]3 years ago
7 0
Find the multiplication by subtracting the second term from the first term
27 - 30 = -3, so the multiplication table is -3x.
Now find the deviation of the first term in this sequence from the first term of the original -3x table
30 - -3 = 33
So you're adding 33 to the terms to get the sequence given
Final equation is:
-3n + 33
patriot [66]3 years ago
5 0
Assuming that the 30 is term #1 ..... The 'n'th term of the series is. T(n) = 33 - 3n or 3 (11 - n).
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umka21 [38]

Answer: 1.4

Step-by-step explanation:

To calculate the grade point average you have to sum all the points of each course multiplying the hours and then diveded by the total number of hours she did.

She earned a grade B in her 4 hour topology course, so she has 3*4 points.

In her 11 hour gouvernment course, she earned a grade D, so she has 1*11 points. In the 2 hour biology course she earned a grade D, so she has 1*2 points and in her 3 hours studio art course she had also a grade D, so she has 1*3 points

She has done 3+2+11+4 hours of subjects=20.

The total average is (3*4+1*11+1*2+1*3)/20=28/20=1.4

8 0
3 years ago
What are the solutions of x² + 6x - 16 = 0?
AveGali [126]

Step-by-step explanation:

x_{1,\:2}=\frac{-6\pm \sqrt{6^2-4\cdot \:1\cdot \left(-16\right)}}{2\cdot \:1}\\\sqrt{6^2-4\cdot \:1\cdot \left(-16\right)}\\\sqrt{6^2+64}\\\sqrt{36+64}\\\sqrt{100}\\\sqrt{10^2}\\=10\\x_1=\frac{-6+10}{2\cdot \:1},\:x_2=\frac{-6-10}{2\cdot \:1}\\\\\bold{x_1:2}\\\frac{-6+10}{2\cdot \:1}\\\frac{4}{2\cdot \:1}\\\frac{4}{2}\\=2\\\\\bold{x_2:-8}\\\frac{-6-10}{2\cdot \:1}\\\frac{-16}{2\cdot \:1}\\\frac{-16}{2}\\-\frac{16}{2}\\=-8

Answer:

x₁ = 2

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6 0
10 months ago
Pls pls help me I will mark you brainest
Ann [662]

Answer:

130

Step-by-step explanation:

10+10+5+5=30

50+50=100

30+100=130

5 0
3 years ago
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Dmitry [639]
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8 0
3 years ago
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BigorU [14]

Answer:

Reflected about the y-axis and then rotated 90° counterclockwise

Step-by-step explanation:

(x , y) to (-x , y) --> reflected over y-axis

then (-x , y)  --> (-y, -x) -->90 degrees rotation counterclockwise

So answer is the last one

Reflected about the y-axis and then rotated 90° counterclockwise

8 0
3 years ago
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