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ipn [44]
3 years ago
8

4.Under NCC training program, students of Vidyalaya stayed in a conical tent made, with a base radius of 7m and height 24m.After

performing whole day program of NCC , students came to their tent for some rest and enjoyment. What is the slant height of the tent?
b. what is the area of the tarpaulin used in making the tent , assuming that all the stitching margins and the wastage is negligible?
c. What is the length of the tarpaulin if its width is 11m?
d. Determine the cost of tarpaulin, if it measuring 1 m2 costs Rs. 5 .
Mathematics
1 answer:
Stells [14]3 years ago
8 0
I have a lot to say about the devil lol
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What are the values of X and Z.
stiv31 [10]

Answer:

x = 12, z  = 86

Step-by-step explanation:

Two angles are called supplementary when their measures add up to 180 degrees.

(12x -58  + 13x - 62 ) = 180°

12 x + 13x -58 - 62 = 180°

25x - 120 = 180

25x = 180 + 120

x = 300/ 25

x = 12

----------------------------------------------------------------------------------

(z° + 13x - 62) = 180

(z° + 13(12) - 62 )= 180

(z° +  156 - 62 )= 180

(z° + 94 ) = 180

z° = 180 - 94

z  = 86

5 0
3 years ago
If sine theta equals three over four, what are the values of cos θ and tan θ?
ratelena [41]

Answer:

In words, Cosine theta equals plus or minus square root of seven over 4,tangent theta equals plus or minus  three over root seven

Step-by-step explanation:

Given that sin ∅ =3/4 It means the ratio of the opposite side to the hypotenuse side is 3:4.

Using the Pythagoras theorem we can calculate the hypotenuse adjacent as follows.

a²+b²=c²

a²=c²-b²

a²=4²-3²

a²=16-9

a²=7

a=√7

Then Cos ∅= opposite/ adjacent

=√7/4

Then Tan ∅ = opposite/adjacent

=3/√7

In words, Cosine theta equals plus or minus square root of seven over 4,tangent theta equals plus or minus  three over root seven.

7 0
3 years ago
Write a polynomial that represents the area of the shaded region
marusya05 [52]
<h3>Answer: x^2-3x+36</h3>

=========================================

Explanation:

The larger rectangle has area of (x+1)(x+1) = x^2+2x+1 through the use of the FOIL rule or distribution

If you use distribution, then it might help to let y = x+1 so we'd have y(x+1) lead to xy+1y which becomes x(x+1)+1(x+1). From there it might be easier to see how to get x^2+2x+1 after everything distributes again and simplifies.

The smaller rectangle has area 5x-35 which is found by distributing 5(x-7)

To get the shaded area, we subtract the two rectangle areas found above

shaded area = (larger area) - (smaller area)

shaded area = (x^2+2x+1) - (5x - 35)

shaded area = x^2+2x+1 - 5x + 35

shaded area = x^2-3x+36

6 0
3 years ago
What is the equal to 3^3.3^5 A. 3−2 B. 32 C. 38 D. 315
lora16 [44]
3^3 \cdot 3^5 = 3^{3+5} = 3^8\\\\\boxed{\bf{C)~3^8}}\\\\\\a^b \cdot a^c = a^{b+c}
3 0
3 years ago
CAN I GET SOMEONES HELP ASAP!!
PIT_PIT [208]
The answer would be <QRZ

Since you are looking for an angle congruent to <UQR using the alternate interior angles theorem, interior suggests that the angle must be inside the parallel lines, se we can get rid of options <WRT and <TRZ since they are exterior angles

Furthermore, in the alternate interior angles theorem, the two angles must be alternate or opposite of each other which would show that the only possible answer would be <QRZ

hope this helped!


7 0
3 years ago
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