Answer:
Step-by-step explanation:
Given equation is,
x² + (p + 1)x = 5 - 2p
x² + (p + 1)x - (5 - 2p) = 0
x² + (p + 1)x + (2p - 5) = 0
Properties for the roots of a quadratic equation,
1). Quadratic equation will have two real roots, discriminant will be greater than zero. [(b² - 4ac) > 0]
2). If the equation has exactly one root, discriminant will be zero [(b² - 4ac) = 0]
3). If equation has imaginary roots, discriminant will be less than zero [(b² - 4ac) < 0].
Discriminant of the given equation = 
For real roots,
p² + 2p + 1 - 8p + 20 > 0
p² - 6p + 21 > 0
For all real values of 'p', given equation will be greater than zero.
Answer: 238$
Step-by-step explanation: 7 x 17 = 119 mutiply this x 2.00 = 238
Answer:
Step-by-step explanation:
To find the area of a rectangle you have to multiply the length by the width.
In your problem, the length and width are both equations, so you just have to multiply each part of the equation separately.
For example, if you were to put both equations with one over the other, you just have to multiply the aligned numbers.
The length is: x2 + 6x + 3
The width is: 3x2 + 4x - 2
and if you multiply the aligned numbers together, you get
3x2 + 24x - 6. Because:
x2 × 3x2 = 3x2,
6x × 4x = 24x,
and 3 × -2 = -6
Important: Use the symbol "^" to denote exponentiation:
<span>x3 – 9x2 + 5x – 45 NO
</span><span>x^3 – 9x^2 + 5x – 45 YES
Look at the first 2 terms. They can be rewritten as x^2(x-9). Then look at the last 2 terms. They can be rewritten as 5(x-9). So, x-9 is the common factor here. Thus, the original expression becomes:
(x^2-5)(x-9).
Note that x^2-5 can be factored, so that the final 3 factors are:
(x-sqrt(5)), (x+sqrt(5)), (x-9).</span>
Interquartile Range is the answer
