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gregori [183]
3 years ago
5

dentify the vertical asymptotes of f(x) = quantity x plus 6 over quantity x squared minus 9x plus 18.

Mathematics
1 answer:
ser-zykov [4K]3 years ago
8 0
So the function we're dealing with is

f(x) = \frac{x+6}{x^{2}-9x+18 }

Factorising we get, x^{2} -9x+18=0
(x-3)(x-6)=0

Therefore, the vertical asymptotes are at x = 3 and x = 6 
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Ajax is 5 and 1 fourth feet tall. His sister is 3 eighths foot shorter than Ajax How tall is Ajax Sister?
user100 [1]

Answer:

4\frac{3}{4} feet tall

Step-by-step explanation:

Ajax is "5 and 1 fourth feet tall", which can be written as the mixed number 5\frac{1}{4} .

His sister is "3 eighths foot shorter", so she's 3/8 feet shorter than 5 1/4.

So, this is just a subtraction problem:

5\frac{1}{4} -\frac{3}{8}

To solve this, we want to convert 5 1/4 into an improper fraction, which is: \frac{21}{4} . Now, we want to find a common denominator. In this case, that common denominator is 8, so \frac{21}{4} =\frac{42}{8} .

Finally, we subtract 3/8 from 42/8: \frac{42}{8} -\frac{3}{8} =\frac{39}{8} . So, Ajax's sister is 39/8 feet. Converting this into a mixed number, we have: 39/8 = 4\frac{6}{8} =4\frac{3}{4} .

Therefore, Ajax's sister is 4\frac{3}{4} feet tall.

Hope this helps!

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4/7<br> of a number is 36<br> What is the number?
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