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Rudiy27
3 years ago
10

Two identical positive charges exert a repulsive force of 6.4x10^-9 N when separated by a distance of 3.8x10^10 m. Calculate the

charge of each.
Physics
1 answer:
aleksley [76]3 years ago
8 0

Answer:F = kq2/d2 ⇒

q = √(Fd2/k)

q = d √(F/k)

d = 3.8 x 10-10 m

F = 6.4 x 10-9 N

Look up k in your physics book in appropriate units, and plug in the numbers. You should get q in coulombs.

Explanation:

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b) R_p=\left | \dfrac{\dfrac{\sqrt{7}}{3}-\dfrac{1.5}{\sqrt{2}}}{\dfrac{\sqrt{7}}{3}+\dfrac{1.5}{\sqrt{2}}} \right |^2

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