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vlada-n [284]
3 years ago
8

A rubber ducky is placed 20 cm from a thin convex lens with a focal length of 15 cm. Which statement correctly describes the nat

ure and position of the image formed of the rubber ducky? A) Real and upright on the side of the lens opposite the rubber ducky. B) Real and inverted on the side of the lens opposite the rubber ducky. C) Imaginary and upright on the side of the lens opposite the rubber ducky. D) Imaginary and inverted on the same side of the lens as the rubber ducky.
Physics
2 answers:
blondinia [14]3 years ago
6 0
I believe the answer is B, a real and inverted image is formed on the side of the lens opposite the rubber ducky. The focal length is 15 cm and therefore the center of curvature (2F) will be 30 cm. When the object is placed between F and 2F (in this case 20 cm) in front of a convex lens, an inverted, real image is formed on the other side of the lens.
andre [41]3 years ago
6 0

Answer:

B

Explanation:

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Explanation:

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Let \theta is the angular distance that the pie plate has moved through.

It is given by :

\theta=\dfrac{d}{r}

\theta=\dfrac{183}{4.5}  

\theta=40.66\ radian

Since, 1 radian = 57.29 degrees

\theta=2329.64\ degrees

Since, 1 radian = 0.159155 revolution

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3 years ago
A coating is being applied to reduce the reflectivity of a pane of glass to light with a wavelength of 522 nm incident near the
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Answer:

  t = 94.91 nm

Explanation:

given,

wavelength of the light = 522 nm

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we know the equation

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   \nu= \dfrac{c}{\nu\lambda}

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the thickness of the coating will be calculated using

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the thickness of the coating will be equal to t = 94.91 nm

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notka56 [123]

Answer:

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Explanation:

Given:

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Also, acceleration acting on the ball is always due to gravity. So, acceleration of the ball is, a=g=-9.8\ m/s^2

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Plug in the given values and solve for 'u'. This gives,

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3 0
3 years ago
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How are some types of collisions different from others?
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