F = normal force by each board on each side
W = weight of the board in between acting in down direction = 95.5 N
f = frictional force in upward direction by each board
= coefficient of friction = 0.663
Using equilibrium of force in Upward direction
f + f = W
f = W/2
f = 95.5/2 = 47.75 N
frictional force is given as
f = F
47.75 = (0.663) F
F = 72.02 N
Answer:
<em>The acceleration of the racecar is</em>
Explanation:
<u>Uniformly Accelerated Motion</u>
It's a type of motion in which the velocity of an object changes by an equal amount in every equal period of time.
Following the definition above, the acceleration is defined as:
Where a is the constant acceleration, vo the initial speed, vf the final speed, and t the time.
The racecar goes from vo=18.5 m/s to vf=46.1 m/s in t=2.47 seconds, thus the acceleration is:
The acceleration of the racecar is
Answer:
Explanation:
<u>Given:</u>
Mass = m = 200,000 kg
Vertical Distance = h = 120 m
Speed = v = 14 m/s
Acceleration due to gravity = g = 10 m/s²
<u>Required:</u>
1) Gravitational Potential Energy = P.E = ?
2) Kinetic Energy = K.E. = ?
<u>Formula:</u>
1) P.E. = mgh
2) K.E. =
<u>Solution:</u>
1) P.E. = (200,000)(10)(120)
P.E. = 240,000,000 Joules
P.E. = 240 Mega Joules
P.E. = 240 MJ
2) K.E. = 1/2 (200000)(14)^2
K.E. = (100000)(196)
K.E. = 19,600,000 Joules
K.E. = 19.6 MJ
Hope this helped!
<h3>~AH1807</h3>