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OlgaM077 [116]
2 years ago
10

In which of the following ways is a puffin dependent upon salmon? Question 4 options: Puffins have a commensalistic relationship

with salmon. Puffins have a parasite-host relationship with salmon. Puffins have a mutualistic relationship with salmon. Puffins have a predator-prey relationship with salmon.
Physics
2 answers:
galben [10]2 years ago
5 0
<span>Puffins have a predator-prey relationship with salmon.

</span>
melomori [17]2 years ago
3 0

Puffins have a predator-prey relationship with salmon

salmon is a fish and is the preferred food for puffins. so in that way puffins are predator that hunts salmon the prey.

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In this schematic, the total resistance is 50 ohms. 100 ohms. 1,000 ohms. 100 ohms 10,000 ohms
Mrrafil [7]

The total resistance of the given circuit is if the circuit contains 100ohms,1000 ohms,100 ohms and 10,000 ohms resistors.

Resistance is measured in ohms, and it is represented by the Greek letter omega (Ω). Ohms are named after Georg Simon Ohm (1784-1854), a German physicist who concentrated on the connection between voltage, current and resistance. He is credited for planning Ohm's Regulation.

Resistance estimations are regularly taken to demonstrate the state of a part or a circuit.

  • The higher the resistance, the lower the ongoing current. On the off chance that strangely high, one potential reason (among many) could be harmed guides because of consuming or erosion.
  • The lower the obstruction, the higher the ongoing stream. Potential causes: protectors harmed by dampness or overheating.

Since resistors are connected in series, so we know that when resistors are connected in series, total resistance is given by the formula

Rₙ=R₁+R₂+R₃+---------------Rₙ

So, resistors value are 50 ohms. 100 ohms. 1,000 ohms. 100 ohms 10,000 ohms.

Therefore, total resistance is 50+100+1000+100+10000=10250ohm

Hence, total resistance is 10250ohm

To know more about resistance, visit here:

brainly.com/question/29427458

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4 0
11 months ago
What is the weight of a 24.52kg Television dropped on pluto(acceleration of 0.59m/s/s)?
jolli1 [7]
W=ma=24.52*0.59 = ...

6 0
3 years ago
Read 2 more answers
Cars A and B are racing each other along the same straight road in the following manner: Car A has a head start and is a distanc
4vir4ik [10]

The question is incomplete. Here is the complete question.

Cars A nad B are racing each other along the same straight road in the following manner: Car A has a head start and is a distance D_{A} beyond the starting line at t = 0. The starting line is at x = 0. Car A travels at a constant speed v_{A}. Car B starts at the starting line but has a better engine than Car A and thus Car B travels at a constant speed v_{B}, which is greater than v_{A}.

Part A: How long after Car B started the race will Car B catch up with Car A? Express the time in terms of given quantities.

Part B: How far from Car B's starting line will the cars be when Car B passes Car A? Express your answer in terms of known quantities.

Answer: Part A: t=\frac{D_{A}}{v_{B}-v_{A}}

              Part B: x_{B}=\frac{v_{B}D_{A}}{v_{B}-v_{A}}

Explanation: First, let's write an equation of motion for each car.

Both cars travels with constant speed. So, they are an uniform rectilinear motion and its position equation is of the form:

x=x_{0}+vt

where

x_{0} is initial position

v is velocity

t is time

Car A started the race at a distance. So at t = 0, initial position is D_{A}.

The equation will be:

x_{A}=D_{A}+v_{A}t

Car B started at the starting line. So, its equation is

x_{B}=v_{B}t

Part A: When they meet, both car are at "the same position":

D_{A}+v_{A}t=v_{B}t

v_{B}t-v_{A}t=D_{A}

t(v_{B}-v_{A})=D_{A}

t=\frac{D_{A}}{v_{B}-v_{A}}

Car B meet with Car A after t=\frac{D_{A}}{v_{B}-v_{A}} units of time.

Part B: With the meeting time, we can determine the position they will be:

x_{B}=v_{B}(\frac{D_{A}}{v_{B}-v_{A}} )

x_{B}=\frac{v_{B}D_{A}}{v_{B}-v_{A}}

Since Car B started at the starting line, the distance Car B will be when it passes Car A is x_{B}=\frac{v_{B}D_{A}}{v_{B}-v_{A}} units of distance.

5 0
2 years ago
A car is up on a hydraulic lift at a garage. The wheels are free to rotate, and the drive wheels are rotating with a constant an
masya89 [10]

Answer:

Explanation:

Given

Wheels are rotating with constant angular velocity let say \omega

Presence of constant angular velocity show that there is no angular acceleration thus there is no tangential acceleration.

But any particle on the rim will experience a constant acceleration towards center called centripetal acceleration.

(a) yes, there will be tangential velocity which is given by

v=r\cdot \omega

where r=radial distance from center

(b)tangential acceleration

there would be no tangential acceleration as velocity is constant

(c)centripetal acceleration

Yes, there will be centripetal acceleration given by

a_c=\omega ^2\times r

                                   

7 0
3 years ago
The fastest pitched baseball was clocked at 46 m/s. assume that the pitcher exerted his force (assumed to be horizontal and cons
Zielflug [23.3K]
Using the Equation:
                                 v² = vi² + 2 · a · s    → Eq.1
where,
v = final velocity 
vi = initial velocity 
a = acceleration 
s = distance 

<span><span>We know that vi = 0 because the ball was at rest initially.
</span><span>
Therefore,

Solving Eq.1 for acceleration,
 
</span></span> v² = vi² + 2 · a · s
 v² = 0 + 2 · a · s
 v² = 2 · a · s
Rearranging for a,
a = v ²/2·<span>s
Substituting the values,
a = 46</span>²/2×1<span> 
a = 1058 m/s</span>² 

<span>Now applying Newton's 2nd law of motion,
 </span>
<span>F = ma
   = 0.145</span>×<span>1058

F = 153.4 N</span>
8 0
3 years ago
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