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OlgaM077 [116]
2 years ago
10

In which of the following ways is a puffin dependent upon salmon? Question 4 options: Puffins have a commensalistic relationship

with salmon. Puffins have a parasite-host relationship with salmon. Puffins have a mutualistic relationship with salmon. Puffins have a predator-prey relationship with salmon.
Physics
2 answers:
galben [10]2 years ago
5 0
<span>Puffins have a predator-prey relationship with salmon.

</span>
melomori [17]2 years ago
3 0

Puffins have a predator-prey relationship with salmon

salmon is a fish and is the preferred food for puffins. so in that way puffins are predator that hunts salmon the prey.

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Assessment started: undefined.
enot [183]

Answer:

Option B: Group

Explanation:

The elements fluorine, chlorine, and iodine are commonly known as halogens.

They all have 7 valence electrons in their outermost shell and thus they all belong to group 7A in the periodic table.

Correct Answer is: Group

5 0
3 years ago
PLZ HELP ON #22-26!!!! <br><br>Please explain why and how you got your answer.
AleksAgata [21]
22. a - (vf^2 - vi^2)/(2d) 
a = (0 - 23^2)/(170) 
a = -3.1 m/s^2

23. Find the time (t) to reach 33 m/s at 3 m/s^2
33-0/t = 3 
33 = 3t 
t = 11 sec to reach 33 m/s^2
Find the av velocuty: 33+0/2 = 16.5 m/s
Dist = 16.5 * 11 = 181.5 meters to each 33m/s speed. Runway has to be at least this long. 

24. The sprinter starts from rest. The average acceleration is found from: 
(Vf)^2 = (Vi)^2 = 2as ---> a = (Vf)^2 - (Vi)^2/2s = (11.5m/s)^2-0/2(15.0m) = 4.408m/s^2 estimated: 4.41m/s^2
The elapsed time is found by solving
Vf = Vi + at ----> t = vf-vi/a = 11.5m/s-0/4.408m/s^2 = 2.61s

25. Acceleration of car = v-u/t = 0ms^-1-21.0ms^-1/6.00s = -3.50ms^-2
S = v^2 - u^2/2a = (0ms^-1)^2-(21.0ms^-1)^2/2*-3.50ms^-2 = 63.0m 

26. Assuming a constant deceleration of 7.00 m/s^2
final velocity, v = 0m/s 
acceleration, a = -7.00m/s^2
displacement, s - 92m 
Using v^2 = u^2 - 2as 
0^2 - u^2 + 2 (-7.00) (92) 
initial velocity, u = sqrt (1288) = 35.9 m/s 
This is the speed pf the car just bore braking. 

I hope this helps!! 

5 0
3 years ago
What happens to the ball's velocity while the ball is traveling upwards?
Bess [88]
If the ball does not have a propeller or jet engine on it, then it is an object
in free fall.  That means its downward speed grows by 9.8 m/s for every
second that it's in the air. 

If it happens to be traveling upward at the moment, then that won't last long. 
Its upward speed is decreasing by 9.8 m/s every second.  It will eventually
run out of upward gas and start moving downward.  At that instant, you might
say that the direction of its velocity has changed by 180 degrees.
7 0
3 years ago
A cross-country skier moves 36 meters eastward, then 44
ivanzaharov [21]

Answer:

Magnitude = 14 metres

Direction = eastward.

Explanation:

A cross-country skier moves 36 meters eastward, then 44meters westward, and finally 22 meters eastward.

Whats the Magnitude and Direction?

The magnitude and direction will be the displacement of the cross country skier.

Let the east ward be positive and the west ward be negative.

Since the skier moves 36 meters eastward, then 44meters westward, and finally 22 meters eastward. Then, that will be:

36 - 44 + 22 = 14

Since the answer is positive, the magnitude is 14 and the direction is east ward.

3 0
3 years ago
A motorcycle has a mass of 2.50×10^2. A constant force is exerted on it for 60.0s. The motorcycles initial velocity is 6.00 m/s
Margarita [4]

The change in momentum is 5500 kg m/s

Explanation:

The change in momentum of an object is given by

\Delta p = m(v-u)

where

m is the mass of the object

v is the final velocity

u is the initial velocity

In this problem, we have:

m=2.50\cdot 10^2 kg (mass of the motorcycle)

v=28.0 m/s (final velocity)

u=6.0 m/s (initial velocity)

Therefore, the change in momentum is

\Delta p=(2.50\cdot 10^2)(28.0-6.0)=5500 kg m/s

Learn more about change in momentum:

brainly.com/question/9484203

#LearnwithBrainly

8 0
3 years ago
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