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Allushta [10]
3 years ago
8

Certain suv ads claim that their vehicles can climb a slope of 45?. what is the minimum coefficient of static friction between t

he tires and the road for this to be possible?
Physics
1 answer:
kotykmax [81]3 years ago
8 0
First, you make a force body diagram to illustrate the problem. Then, apply Newton's laws of motion.

Summation of forces along the y-direction:

F = 0 (bodies at equilibrium) = Normal force - weight*cos45 = 0
Normal force = wcos45

Summation of forcesalong the x-direction:

F = 0 (bodies at equilibrium) = Frictional force - weight*sin45 = 0
x*Normal force - weight*sin45 = 0   (let x be the min coeff of static friction)
x*weight*cos45 = weight*sin 45
x = sin45/cos45 = 1

Therefore, the minimum coefficient of static friction must be 1.
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4) A football player starts at the 40-yard line, and runs to the 25-yard line in 2 seconds.
VMariaS [17]

Answer:

(a). Their speed during that run is 10 m/s.

(b). Their velocity is 6.86 m/s

(c). The final position is at 8.91 m.

Explanation:

Given that,

A football player starts at the 40-yard line, and runs to the 25-yard line in 2 seconds.

Suppose, the distance between 40 yard line and 25 yard line is 20 yard.

(a). We need to calculate their speed during that run

Using formula of speed

v=\dfrac{d}{t}

Where. d = distance

t = time

Put the value into the formula

v=\dfrac{18.288}{2}

v=10\ m/sduring that run

(b). We need to calculate their velocity

Using formula of speed

v=\dfrac{\Delta d}{\Delta t}

Put the value into the formula

v=\dfrac{22.86-36.58}{2}

v=-6.86\ m/s

Negative sign shows the direction of motion.

(c). If they kept running at that velocity for another 1.3 seconds,

We need to calculate the final position

Using formula of position

d=vt

Put the value into the formula

d=6.86\times1.3

d=8.91\ m

Hence, (a). Their speed during that run is 10 m/s.

(b). Their velocity is 6.86 m/s

(c). The final position is at 8.91 m.

8 0
3 years ago
Which are two types of mechanical energy electrical and kinetic nuclear and chemical radiant and thermal elastic and gravitation
WINSTONCH [101]
Elastic and gravitational.
5 0
3 years ago
Read 2 more answers
What is one way to increase the amplitude if a wave in a medium?
Gekata [30.6K]

Answer: c

Explanation:

3 0
4 years ago
A box of weight 74 N is sliding on a horizontal surface at a constant velocity due to an external force F-> of magnitude 4.8
n200080 [17]

Answer

4.8 N

If the box is moving with a constant velocity, then we can say that the system is in equilibrium. This is because if the external force (F->) was greater than other forces the box would be accelerating. This tells us that this force (F->) is just enough to overcome friction and so it must be equal to 4.8 N.

The normal force has no effect to the horizontal velocities or forces. It is equal to -Weight. That is -74 N. The negative sign shows that the force is in opposite direction.

6 0
3 years ago
a motorcycle starts from rest covers 200 meter distance in 6 second calculate final velocity and acceleration​
Ivanshal [37]

Explanation:

s = ut + 1/2 a t^2

200 = 0 * 6 + 1/2 * a * (6)^2

200 = 1/2 * a * 36

200 = 18 a

a = 200/18

a= 11.1m/sec^2

v = u + at

v = 0 + 11.1 * 6

v = 66.6m/s

hope it helps you

3 0
3 years ago
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