6. Write in exponential form: log(3)81 = 4
1 answer:
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Given:
and,
K = 1
We would require to do the synthetic division of the above problem in order to know whether K=1 is a lower bound or not. Let's do it!
Steps of Synthetic Division:
1. Write the coefficients of the equation, and before that write 1. Like,
1 ║ 4 -2 2 4
As you can see, the coefficients of the equation are seperated by ║.
2. Drop down the first value after ║as it is. Like:
1 ║ 4 -2 2 4
:
----------------------
4
3. Multiply 4 with 1 and then place the resultant value under -2 and then add that resultant value with -2. Like
1 ║ 4 -2 2 4
: 4
----------------------
4 2
4. Repeat Step 3 until you're done.
1 ║ 4 -2 2 4
: 4 2
----------------------
4 2 4
1 ║ 4 -2 2 4
: 4 2 4
----------------------
4 2 4 8
Now every value, +4, +2, +4, +8, under the bar(---------) is positive; therefore, it means that K=1 is the upper bound, NOT lower bound.
Ans: K=1 is NOT a lower bound.
-i
and,
K = 1
We would require to do the synthetic division of the above problem in order to know whether K=1 is a lower bound or not. Let's do it!
Steps of Synthetic Division:
1. Write the coefficients of the equation, and before that write 1. Like,
1 ║ 4 -2 2 4
As you can see, the coefficients of the equation are seperated by ║.
2. Drop down the first value after ║as it is. Like:
1 ║ 4 -2 2 4
:
----------------------
4
3. Multiply 4 with 1 and then place the resultant value under -2 and then add that resultant value with -2. Like
1 ║ 4 -2 2 4
: 4
----------------------
4 2
4. Repeat Step 3 until you're done.
1 ║ 4 -2 2 4
: 4 2
----------------------
4 2 4
1 ║ 4 -2 2 4
: 4 2 4
----------------------
4 2 4 8
Now every value, +4, +2, +4, +8, under the bar(---------) is positive; therefore, it means that K=1 is the upper bound, NOT lower bound.
Ans: K=1 is NOT a lower bound.
-i
