Answer:
d. Reject the claim that mean is 40 MPG when it is actually 40 MPG.
Step-by-step explanation:
The type 1 error could be said to have been made if the null hypothesis is erroneously rejected.
In the scenario above :
The null hypothesis (H0) : mean = 40
Hence, if the Null hypothesis defined above is rejected when in fact the hypothesis that the mean miles per gallon is actually 40.
On the other hand, the type 2 error occurs when a null which is false is not rejected.
Hence, when a true null is rejected, a type 1 error is committed. Similarly, when a false null isn't rejected, then a type 2 error has been committed.
Answer:
The equations describing the area which each tower covers are given as
Tower A : 
Tower B : 
Tower C : 
Step-by-step solution:
Cell phone radio towers broadcast a cell phone signal in circular pattern
Tower A at Adele Acres have position co-ordinates as (0,0) and a coverage radius of 4 ml. So, the area which it covers is given by the equation,
-------------------------------(1)
Tower B at Brown Lake have position co-ordinates as (5,4) and a coverage radius of 3 ml. So, the area which it covers is given by the equation,
-------------------------------(2)
Tower C at Cady City have position co-ordinates as (4,-4) and a coverage radius of 5 ml. So, the area which it covers is given by the equation,
-------------------------------(2)
INPUT SU,0 IF OFF OUTPUT M,0 OUTPUT T,0 OUTPUT W,0 OUTPUT TH,0 OUTPUT F,0 ELSE ON OUTPUT M,0 OUTPUT T,0 OUTPUT W,0 OUTPUT TH,0 O
Karo-lina-s [1.5K]
Why’s it in all caps and what’s the question this doesn’t look like a math equation
Transaction 3 - $143
transaction 4 - $-86
transaction 5 - $86
ANSWER
x = 1.2226
EXPLANATION
To solve this equation we have to apply the property of the logarithm of the base,

Thus, we can apply the natural logarithm - whose base is e, to both sides of the equation,

Now we apply the property of the logarithm of a power,

In our equation,

Then divide both sides by 4 and solve,

The solution to this equation is x = 1.2226, rounded to four decimal places.