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3 years ago

8

Your teacher says he will give you 2200 seconds to complete the practice quiz, how long is this in hours? Express your answer ro

unded to the nearest hundredth of an hour.

1 answer:

Rama09 [41]3 years ago

7 0

0.611 hour

hope this helps!

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Growth factors for the population of Atlanta in the past five years have been 1, 2, 3, 4 , and 5. The geometric mean is a. . b.

choli [55]

Answer:

The geometric mean of given data is approximately 2.6051

Step-by-step explanation:

We are given the following data in the question:

1, 2, 3, 4, 5.

We have to find the geometric mean.

Formula:

$(a_1\times a_2\times... \times a_n)^{\frac{1}{n}}$

Putting the values, we get,

$\text{Geometric mean} = (1\times 2\times 3\times 4 \times 5)^{\frac{1}{5}}\\=(120)^{\frac{1}{5}} \approx 2.6051$

Thus, the geometric mean of given data is approximately 2.6051

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4 years ago

The weight of an adult swan is normally distributed with a mean of 26 pounds and a standard deviation of 7.2 pounds. A farmer ra

Snezhnost [94]

Let $X$ denote the random variable for the weight of a swan. Then each swan in the sample of 36 selected by the farmer can be assigned a weight denoted by $X_1,\ldots,X_{36}$ , each independently and identically distributed with distribution $X_i\sim\mathcal N(26,7.2)$ .

You want to find

$\mathbb P(X_1+\cdots+X_{36}>1000)=\mathbb P\left(\displaystyle\sum_{i=1}^{36}X_i>1000\right)$

Note that the left side is 36 times the average of the weights of the swans in the sample, i.e. the probability above is equivalent to

$\mathbb P\left(36\displaystyle\sum_{i=1}^{36}\frac{X_i}{36}>1000\right)=\mathbb P\left(\overline X>\dfrac{1000}{36}\right)$

Recall that if $X\sim\mathcal N(\mu,\sigma)$ , then the sampling distribution $\overline X=\displaystyle\sum_{i=1}^n\frac{X_i}n\sim\mathcal N\left(\mu,\dfrac\sigma{\sqrt n}\right)$ with $n$ being the size of the sample.

Transforming to the standard normal distribution, you have

$Z=\dfrac{\overline X-\mu_{\overline X}}{\sigma_{\overline X}}=\sqrt n\dfrac{\overline X-\mu}{\sigma}$

so that in this case,

$Z=6\dfrac{\overline X-26}{7.2}$

and the probability is equivalent to

$\mathbb P\left(\overline X>\dfrac{1000}{36}\right)=\mathbb P\left(6\dfrac{\overline X-26}{7.2}>6\dfrac{\frac{1000}{36}-26}{7.2}\right)$
$=\mathbb P(Z>1.481)\approx0.0693$

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3 years ago

Question Progress

marin [14]

51cm / 3 X 5 = 85cm
Jijdididjdidjdjdjd

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3 years ago

HELP ME NOW PLS ITS PYTHAGOREAN THEOREM IM FAILING THIS PLS PLS PLS :(

Savatey [412]

Answer:

11

Step-by-step explanation:

Add the numbers and then boom answer (i think and hope)

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