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2 years ago

I’ll give brainliest HELO ASAP PLZ!!

Mathematics

2 answers:

Helen [10]2 years ago

5 0

Answer:

Step-by-step explanation:

Yakvenalex [24]2 years ago

5 0

Answer is definitely a

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I need help I can’t figure it out

dusya [7]

Answer:

$\large\boxed{\dfrac{41p}{70q^4(r-9)^2}}$

Step-by-step explanation:

$\dfrac{2p^4}{5q^5(r-9)^3}\cdot\dfrac{41q(r-9)}{28p^3}\\\\=\dfrac{2\!\!\!\!\diagup^1\cdot41}{5\cdot28\!\!\!\!\!\diagup_{14}}\cdot\dfrac{q\!\!\!\!\diagup}{q^{5\!\!\!\!\diagup^4}}\cdot\dfrac{(r\!\!\!\!\!\!{--}-9)\!\!\!\!\!\!{--}}{(r-9)^{3\!\!\!\!\diagup^2}}\cdot\dfrac{p^{4\!\!\!\!\diagup}}{p^3\!\!\!\!\!\!\diagup}\\\\=\dfrac{41}{70}\cdot\dfrac{1}{q^4}\cdot\dfrac{1}{(r-9)^2}\cdot\dfrac{p}{1}\\\\=\dfrac{41p}{70q^4(r-9)^2}$

7 0

2 years ago

Two people are standing on opposite sides of a hill. Person A makes an angle of elevation of 65° with the top of the hill and pe

8090 [49]

Answer:

Option 3. 71 ft. is the distance between B and top of the hill.

Step-by-step explanation:

Let the height of the hill is h ft and the distance of A from the hill be x ft and distance from B to hill is y.

It is given distance between A and B is 45 ft. ∠BAO = 65° and ∠ABO = 80°.

We have to find the distance of B from the top of the hill.

Now from ΔACO $tan 65 = \frac{h}{45-x} = 2.14$

$h=2.14(45-x)$

From ΔBCO $tan80 = \frac{h}{x} = 5.67$

h = 5.67x

Now h = 5.67x = 2.14(45-x)

5.67x = 96.3 - 2.14x

2.14x + 5.67x = 96.3

7.81x = 96.3

x = 96.3/7.81 = 12.33 ft

Therefore $cos80 = \frac{x}{OB}$

$0.174 = \frac{12.33}{OB}$

$OB = \frac{12.33}{.174}=70.86=71ft.$

Therefore 71 ft is the distance between B and the top of the hill.

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3 years ago

A rectangular room is 12.5 feet wide and 14 feet long. How many linear feet of baseboards are needed to trim the room?

QveST [7]

If you do width times length you will get 30. Good luck

8 0

3 years ago

If g (x) = 1/x^2 then g (x+h) - g (x)/h

nignag [31]

$\bf g(x)=\cfrac{1}{x^2}~\hspace{5em}\cfrac{g(x+h)-g(x)}{h}\implies \cfrac{\frac{1}{(x+h)^2}-\frac{1}{x^2}}{h} \\\\\\ \textit{using the LCD of }(x+h)^2(x^2)\qquad \cfrac{\frac{x^2-(x+h)^2}{(x+h)^2(x^2)}}{h}\implies \cfrac{x^2-(x+h)^2}{h(x+h)^2(x^2)} \\\\\\ \cfrac{x^2-(x^2+2xh+h^2)}{h(x+h)^2(x^2)}\implies \cfrac{\underline{x^2-x^2}-2xh-h^2}{h(x+h)^2(x^2)}\implies \cfrac{-2xh-h^2}{h(x+h)^2(x^2)}$

$\bf \cfrac{\underline{h}(-2x-h)}{\underline{h}(x+h)^2(x^2)}\implies \cfrac{-2x-h}{(x+h)^2(x^2)}\implies \cfrac{-2x-h}{(x^2+2xh+h^2)(x^2)} \\\\[-0.35em] ~\dotfill\\\\ ~\hfill \cfrac{-2x-h}{x^4+2x^3h+x^2h^2}~\hfill$

4 0

3 years ago

Pls help me on this question

Anna35 [415]

Answer:

Step-by-step explanation:

7 0

2 years ago

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