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3 years ago

4.Find the slope. Make sure to reduce.

Mathematics

2 answers:

arsen [322]3 years ago

5 0

Answer:

slope=1

Step-by-step explanation:

slope intercept form is y=mx+b.

m=rise over run

starting at the bottom dot, if you count up to the same line it is 4, and counting to the right is also 4, so its 4/4

4 over 4 can be simplified to 1

so the slope is 1

ikadub [295]3 years ago

3 0

Answer:

1 !

Step-by-step explanation:

if you would use RISE/RUN, you see that you go up four and to the right four. since there are no negative numbers, its not negative, and that the slope is 4/4, which simplifies to 1.

i really hope this helps !!

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How it came to this

ryzh [129]

You were really close :D
The mistake you made is that 44 - 36 is 8, not 6.
Using 8 instead, the answer is:
$3~\frac{8}{12}=3~\frac{3}{4},~or~3.75$

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3 years ago

The sum of two numbers is 68. The second number is 2 more than twice the first.

e-lub [12.9K]

Answer:

22 and 46

Step-by-step explanation:

let

one number is x

another is 2x+2

now 2x+2+x=68

or, 3x+2=68

3x=66

or x=66/3=22

so one number is 22 and another is (22X2+2)=46

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3 years ago

Which equation is correct? arccsc(x)=1/cos(x)

viva [34]

Answer:

arccsc(x)=1/cos(x)

Step-by-step explanation:

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3 years ago

Phoebe wants to get atleast a grade of 90 in the math class. Her grade will be the average of two tests. She scored a 94 on the

marin [14]

First things first, you will have 94 + x. Place those on top of a fraction bar and on the bottom put the two numbers over 2. So you have 94 + x over 2. Then, write the symbol ‘greater than or equal to’ and on the other side place your 90. So, 90 + x over 2 is greater than or equal to 90. This is a difficult thing to write out and explain so I hope this makes sense. :)

7 0

3 years ago

Read 2 more answers

Altitudes AA1 and BB1 are drawn in acute △ABC. Prove that A1C·BC=B1C·AC

Sophie [7]

Answer:

See the attached figure which represents the problem.

As shown, AA₁ and BB₁ are the altitudes in acute △ABC.

△AA₁C is a right triangle at A₁

So, Cos x = adjacent/hypotenuse = A₁C/AC ⇒(1)

△BB₁C is a right triangle at B₁

So, Cos x = adjacent/hypotenuse = B₁C/BC ⇒(2)

From (1) and (2)

∴ A₁C/AC = B₁C/BC

using scissors method

∴ A₁C · BC = B₁C · AC

7 0

3 years ago