Answer:
(a) 11.25 and 1.68
(b) 0.1651
(c) 0.3903
(d) 0.6865
Step-by-step explanation:
We are given that GTC, the Georgetown Telephone Company, reports it can resolve customer problems the same day they are reported in 75% of the cases and suppose the 15 cases reported today are representative of all complaints.
This situation can be represented through Binomial distribution as;
where, n = number of trials (samples) taken = 15
r = number of success
p = probability of success which in our question is % of cases in
which customer problems are resolved on the same day, i.e.;75%
So, here X ~
(a) Expected number of problems to be resolved today = E(X)
E(X) =
= n * p = 15 * 0.75 = 11.25
Standard deviation =
=
=
= 1.68
(b) Probability that 10 of the problems can be resolved today = P(X = 10)
P(X = 10) =
=
= 0.1651
(c) Probability that 10 or 11 of the problems can be resolved today is given by = P(X = 10) + P(X = 11)
=
=
= 0.3903
(d) Probability that more than 10 of the problems can be resolved today is
given by = P(X > 10)
P(X > 10) = P(X = 11) + P(X = 12) + P(X = 13) + P(X = 14) + P(X = 15)
=
=
= 0.6865
Answer:
Quadratic formula is in the 2nd picture.
Step-by-step explanation:
Answers in the photo.
Solve the equation for r by finding a,b, and c of the quadratic then applying the quadratic formula.
Your answer is A
It cannot be C because the line y > -2 uses the (>) greater than symbol.
When equations have a greater than symbol, they are graphed using a <u>dotted line. </u>
It cannot be D because the line is y ≤ - l x-1 l
with the less than or equal to sign (≤) , you use a <u>solid line</u> to graph
With the<u> greater than</u> symbol for y > -2 , the shaded region must be <em>above </em>this line.
With the <em>less than </em>or equal to sign in y ≤ - l x-1 l , the shaded region must be <em>below </em>the line.
Hope I helped - message me if you have any questions :)
15 tsp of black pepper was used. 2 half tsp = one whole tsp. 12 half tsp is equivalent to 6 tsp. Multiply 1 1/4 by 12 and you get 15. <span />
y=x+14 line 1
y=3x+2 line 2
These are both the equation of lines written in slope intercept form
y=mx+b where m is the slope and the point (0,b) is the y intercept.
The first line has a slope of m=1. The 2nd line has a slope of m=3
Since these lines have different slopes, they are not parallel, thus they will cross at some point. What you have to determine is where the lines cross, which will be a point (x,y) that is on both lines.
We already have y solved in terms of x from either equation so we can use substitution to solve the system.
Since y=x+14 from line 1, put x+14 in place of y in the equation of line 2.
x+14=3x+2
solve for x.
Subtract x from both sides...
14= 3x-x+2
14=2x+2
subtract 2 from both sides
14-2=2x
12=2x
divide both sides by 2
6=x
We now have the x value of the common point. Plug the value 6 in for x in one of the original equations and solve for y.
y=6+14
y=20
These two lines cross at the point (6,20) which is a point the two lines have in common.
Hope I helped (SharkieOwO)