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3241004551 [841]
3 years ago
15

Twelve and three tenths more than five and thirteen thousandths of a number d is equal to fifteen and three hundred two thousand

ths. What is the value of d?
Mathematics
1 answer:
Masja [62]3 years ago
7 0
12 and 3/10 more than 5 and 13/1000 of d equals 15 and 302/1000
12 and 3/10+(5 and 13/1000 times d)=15 and 302/1000
convert to improper fractions
12 and 3/10=123/10
5 and 13/1000=5013/1000
15 and 302/1000=15302/1000

123/10+(5013/1000 times d)=15302/1000
subtract 123/10 from both sides
123/10=12300/1000
(15302-123000)/1000=2698/1000
5013/1000 times d=2698/1000
multiply both sides by 1000/5013 to clear fraction
d=2698/5013

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dimulka [17.4K]

Answer:

False

Step-by-step explanation:

0.15/10 equals 0.015

6 0
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belka [17]
<h3><u>Answer:</u></h3>

\boxed{\boxed{\pink{\bf \leadsto Hence \ option\ [d]\ \bigg(y =  \dfrac{5}{2}x + 5\bigg) \ is \ correct  }}}

<h3><u>Step-by-step explanation:</u></h3>

Here from the given graph we can see that the graph the graph intersects x axis at (2,0) and y axis at (5,0). On seeing options it's clear that we have to use Slope intercept form . Which is :-

\large\boxed{\orange{\bf y = mx + c} }

We know that slope is \tan\theta. So here slope will be ,

\red{\implies slope = \tan\theta} \\\\\implies slope =\dfrac{PERPENDICULAR}{BASE} \\\\\bf \implies slope =\dfrac{5}{2}

Hence the slope is 5/2 . And here value of c will be 5 since it cuts y axis at (5,0).

\purple{\implies y = mx + c }\\\\\implies y = \dfrac{5}{2}x + 5 \\\\\underline{\boxed{\red{\tt \implies y = \dfrac{5}{2}x + 5 }}}

<h3><u>Hence</u><u> </u><u>option</u><u> </u><u>[</u><u> </u><u>d</u><u> </u><u>]</u><u> </u><u>is</u><u> </u><u>corre</u><u>ct</u><u> </u><u>.</u><u> </u></h3>
4 0
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Norma-Jean [14]

Answer: x=30 (Sorry for wasting your time if the answer is wrong)


Step-by-step explanation:

I did it the lazy way

80-20=60

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(If this is completely wrong then again, sorry)

8 0
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A ball is thrown from an initial height of 2 feet with an initial upward velocity of 29 ft/s. The balls height (h) [in feet] aft
nirvana33 [79]
The ball is at a height of 14 feet after 1.17 and 0.64 seconds.

This is an example of a quadratic equation. Write out the equation with 14 in the place of the height. Then, set it equal to zero.

14 = 2 + 29t - 16t^2

0 = -16t^2 + 29t -12

Now, we can use the quadratic equation to solve.
A = -16
B = 29
C = -12

You will get the solutions of 1.17 and 0.64.
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jeka94
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