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blagie [28]
3 years ago
10

Please help me solve this

Mathematics
1 answer:
dalvyx [7]3 years ago
3 0

Answer:

each \: ribeye \: costs \:  \boxed{(r) \to \: \$23.3664} ......................... .. \\  each \: grilled \:  salmon \:  dinners \: costs \:  \boxed{(r) \to \:  \$18.29912}

Step-by-step explanation:

let \: ribeye \: be \to \: (r).......................... \\ let \: grilled  \: salmon \:  dinners \: be \to \: (g) \\  \tt{hence}  \to\\ (5) \times  17r + 10g =  \$580.22 \\(10)  \times 21r + 5g =  \$582.19 \\  \to \\ (85r + 50g = 2,901.1) \\  - (minus)\\  (210r + 50g =5,821.9 ) \\  - 125r =  - 2,920.8 \\ r =  \frac{ -2,920.8 }{ - 125}  \\  \boxed{r = \$23.3664} \\  \tt{hence}  \to\\17r + 10g =  \$580.22 \\ 17(23.3664) + 10g =  \$580.22 \\1 0g = \$580.22 - \$397.2288 \\ 10g = \$182.9912 \\ g =  \frac{\$182.9912}{10}  \\  \boxed{g = \$18.29912}

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Answers:

<u>Reduce:</u>

Here we gave to simplify the expressions:

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Rearranging the terms:

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Grouping similar terms and factoring:

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