All categories

4 years ago

Factor completely 4x2 - 121

Mathematics

2 answers:

zepelin [54]4 years ago

5 0

Answer:-113

Step-by-step explanation:

You do 4x2 = 8 and then take 121 away from 8 which is -113

anzhelika [568]4 years ago

4 0

Answer:

(2x+11)x (2x-11)

Step-by-step explanation:

You might be interested in

Tickets for a Texans game are on sale. Children, adult, and a senior admission

WARRIOR [948]

Answer:

Step-by-step explanation:

EQUATION - a statement that the values of two mathematical expressions are equal (indicated by the sign =)

Just write down how you would figure out the cost per game.

first game is 7 people times $8.50 =

and so on

This word problem is a great example of needing to pull out only information you need and ignoring the rest.

6 0

4 years ago

4 radical 7 * 2 radical 10

Oliga [24]

Remember
(ab)(cd)=(a)(b)(c)(d)
and
(√a)(√b)=√(ab)

so
(4√7)(2√10)=(4)(√7)(2)(√10)=(4)(2)(√7)(√10)=(8)(√70)=8√70

8 0

4 years ago

Which of the following best describes algebraic expression 10 X +2

sp2606 [1]

Answer:

The answer is basically just 10 times whatever x is, plus 2. For an example, if x was 5, than the answer would be 52 because 10 times 5 plus 2 is 52.

Step-by-step explanation:

6 0

3 years ago

Estimate the unit rate

____ [38]

12÷2.35= 5.10 or 2.35÷ 12= 0.195

4 0

3 years ago

Quadratic Formula to solve the equation x^2- 4x = - 7

mylen [45]

roots of the equation x^2- 4x = - 7 are 2+3i and 2-3i

What are the natures of root of quadratic equation?

Case I: $4ac > b^2$

The roots of the quadratic equation $ax^2 + bx + c = 0$ are real and unequal when a, b, and c are real numbers, a 0, and the discriminant is positive.

Situation II: $b^2$ $-4ac$ =0

The roots and of the quadratic equation $ax^2 + bx + c = 0$ are real and equal when a, b, and c are real numbers, a 0, and the discriminant is zero.

Case III: $b^2$ $-4ac$ <0

The quadratic equation $ax^2 + bx + c = 0$ has roots when a, b, and c are real numbers, a 0, and the discriminant is negative, but these roots are not equal and are not real. We refer to the roots in this instance as fictitious.

Case IV: Perfect square and $b^2 - 4ac > 0$

The roots of the quadratic equation $ax^2 + bx + c = 0$ are real, rational, and unequal when a, b, and c are real numbers, a 0, and the discriminant is positive and perfect square.

Quadratic Formula $x={\frac {-b\pm {\sqrt {b^{2}-4ac}}}{2a}}$