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Anna11 [10]
2 years ago
13

Solve tree he system of equations by the substitution method. 12x + 3y =8 -4x = y + 8

Mathematics
1 answer:
AURORKA [14]2 years ago
7 0

Answer:

8x + 2y

Step-by-step explanation:

12x + 3y = 8 you need to transfer the no. 8 to left since it's positive, it will be negative once you tranfer that and the result is this 8x + 3y -8 =0. Then do it again on the second given, -4x = y + 8.

Tranfer the y variable to left, y is positive then it will be a negative. No need to transfer the no. 8. Then the result would be -4x - y + 8=0

To this solve this, wrote it like this:

12x + 3y –8

-4x - y + 8

——————

8x + 2y

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3 years ago
Calculate the distances between points A & B
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8 0
1 year ago
Express<br><br> 2x^2+3x/(2x+3)(x-2) - 6/x^2-x-2 <br><br> As a single fraction in its simplest form.
Dmitry [639]

Answer:

(x + 3)/(x + 1) .

Step-by-step explanation:

2x^2 + 3x/(2x + 3)(x - 2) - 6 /x^2 - x - 2

= 2x^2 + 3x/(2x + 3)(x - 2) - 6 / (x - 2)(x + 1)

The LCM is (2x + 3)(x - 2)(x + 1) so we have

(2x^2 + 3x)(x + 1) - 6(2x + 3)          x( 2x + 3)(x + 1) - 6(2x + 3)

--------------------------------------- =        ------------------------------------

    (2x + 3)(x - 2)(x + 1)                         (2x + 3)(x - 2)(x + 1)


       (2x + 3)(x(x + 1) - 6)           (2x + 3)(x - 2)(x + 3)

=    ----------------------------  =       ---------------------------     =  (x + 3)/(x + 1)

     (2x + 3)(x - 2)(x + 1)             (2x + 3)(x - 2)(x + 1)  

7 0
3 years ago
The value of x in the equation log(x-1)9=2 is
mel-nik [20]
\log_{(x-1)} 9=2

the domain:
x-1 >0 \ \land \ x-1 \not=1 \\&#10;x>1 \ \land \ x \not= 2 \\&#10;x \in (1; 2) \cup (2;+\infty)

the equation:
\log_{(x-1)}9=2 \\&#10;(x-1)^2=9 \\&#10;\sqrt{(x-1)^2}=\sqrt{9} \\&#10;|x-1|=3 \\&#10;x-1=3 \ \lor \ x-1=-3 \\&#10;x=4 \ \lor \ x=-2

4 is in the domain
-2 is not in the domain

The answer:
x=4

***
Also, the answer in 13 is {8}. -3 is not in the domain. Replace x with -3 and you'll see:
x=\sqrt{5x+24} \\&#10;-3=\sqrt{5 \times (-3)+24} \\&#10;-3=\sqrt{-15+24} \\&#10;-3=\sqrt{9} \\&#10;-3=3
It's not true so -3 isn't a solution to this equation.
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3 years ago
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