All categories

3 years ago

What is 1 1/4 + -3 5/6

Mathematics

1 answer:

julia-pushkina [17]3 years ago

4 0

Answer:

$-2\frac{7}{12}$

Step-by-step explanation:

Convert the mixed numbers to improper fractions, then find the LCD and combine and getting you -2 7/12

<u>Hopes this helps</u>

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1. Define sets

Rudik [331]

Answer:

Set is a collection of specified object.
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Infinite Set. A set which contains infinite number of elements is called an infinite set. ...

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Proper Subset. ...

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4 0

3 years ago

What two numbers when added equal 25 and when multiplied = -200

Igoryamba

The numbers are irrational, so I can't write them exactly with digits.
When rounded to the nearest ten-thousandth, they are

31.3746
and
-6.3746 .

3 0

3 years ago

Substitute the values for a, b, and c into b2 – 4ac to determine the discriminant. Which quadratic equations will have two real

hoa [83]

Answer: $0=2x^2-7x-9\\0=4x^2-3x-1\\0=x^2-2x-8$

Step-by-step explanation:

We know that the standard quadratic equation is ax^2+bx+c=0

Let's compare all the given equation to it and , find discriminant.

1. a=2, b= -7, c=-9

$b^2-4ac=(-7)^2-4(2)(-9)=49+72>0$

So it has 2 real number solutions.

2. a=1, b=-4, c=4

$b^2-4ac=(-4)^2-4(1)(4)=16-16=0$

So it has only 1 real number solution.

3. a=4, b=-3, c=-1

$b^2-4ac=(-3)^2-4(4)(-1)=9+16=25>0$

So it has 2 real number solutions.

4. a=1, b=-2, c=-8

$b^2-4ac=(-2)^2-4(1)(-8)=4+32=36>0$

So it has 2 real number solutions.

5. a=3, b=5, c=3

$b^2-4ac=(5)^2-4(3)(3)=25-36=-9$

Thus it does not has real solutions.

5 0

3 years ago

Read 2 more answers

a chef bought 3 bags of beans. Each bag contains 1 2/5 kilogram of beans. How many kilograms of beans did she buy?

soldi70 [24.7K]

Answer:

4.2 kilograms

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

Can anyone help me out on this question?

svp [43]

Firstly , we will check continuity at x=1

we can use method

Suppose, f(x) is continuous at x=c

then it must satisfy

$\lim_{x \to c} f(x)=f(c)$

$\lim_{x \to 1} f(x)=f(1)$

firstly , we can find limit

$\lim_{x \to 1-} f(x)= \lim_{x \to 1-}(x+3)=1+3=4$

$\lim_{x \to 1+} f(x)= \lim_{x \to 1-}(3x+1)=3*1+1=4$

so, we get

$\lim_{x \to 1} f(x)= 4$

now, we can find f(1)

$f(1)=3*1+1=4$

so, we got

$\lim_{x \to 1} f(x)=f(1) =4$

so, this is continuous at x=1

Hence , option-D...........................Answer

5 0

3 years ago