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artcher [175]
3 years ago
13

What is 1 1/4 + -3 5/6

Mathematics
1 answer:
julia-pushkina [17]3 years ago
4 0

Answer:

-2\frac{7}{12}

Step-by-step explanation:

Convert the mixed numbers to improper fractions, then find the LCD and combine and getting you -2 7/12

<u>Hopes this helps</u>

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1. Define sets
Rudik [331]

Answer:

  • Set is a collection of specified object.
  • The types of set are Finite Set. A set which contains a definite number of elements is called a finite set. ...

Infinite Set. A set which contains infinite number of elements is called an infinite set. ...

Subset. ...

Proper Subset. ...

Universal Set. ...

Empty Set or Null Set. ...

Singleton Set or Unit Set. ...

Equal Set.

  • The operation used on sets are. 1 Intersection 2.Union 3.Difference 4.Compelement

4 0
3 years ago
What two numbers when added equal 25 and when multiplied = -200
Igoryamba
The numbers are irrational, so I can't write them exactly with digits.
When rounded to the nearest ten-thousandth, they are

       31.3746
and
       -6.3746 .
3 0
3 years ago
Substitute the values for a, b, and c into b2 – 4ac to determine the discriminant. Which quadratic equations will have two real
hoa [83]

Answer: 0=2x^2-7x-9\\0=4x^2-3x-1\\0=x^2-2x-8


Step-by-step explanation:

We know that the standard quadratic equation is  ax^2+bx+c=0

Let's compare all the given equation to it and , find discriminant.

1. a=2, b= -7, c=-9

b^2-4ac=(-7)^2-4(2)(-9)=49+72>0

So it has 2 real number solutions.

2. a=1, b=-4, c=4

b^2-4ac=(-4)^2-4(1)(4)=16-16=0

So it has only 1 real number solution.

3. a=4, b=-3, c=-1

b^2-4ac=(-3)^2-4(4)(-1)=9+16=25>0

So it has 2 real number solutions.

4. a=1, b=-2, c=-8

b^2-4ac=(-2)^2-4(1)(-8)=4+32=36>0

So it has 2 real number solutions.

5. a=3, b=5, c=3

b^2-4ac=(5)^2-4(3)(3)=25-36=-9

Thus it does not has real solutions.



5 0
3 years ago
Read 2 more answers
a chef bought 3 bags of beans. Each bag contains 1 2/5 kilogram of beans. How many kilograms of beans did she buy?
soldi70 [24.7K]

Answer:

4.2 kilograms

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
Can anyone help me out on this question?
svp [43]

Firstly , we will check continuity at x=1

we can use method

Suppose, f(x) is continuous at x=c

then it must satisfy

\lim_{x \to c} f(x)=f(c)

\lim_{x \to 1} f(x)=f(1)

firstly , we can find limit

\lim_{x \to 1-} f(x)=  \lim_{x \to 1-}(x+3)=1+3=4

\lim_{x \to 1+} f(x)=  \lim_{x \to 1-}(3x+1)=3*1+1=4

so, we get

\lim_{x \to 1} f(x)= 4

now, we can find f(1)

f(1)=3*1+1=4

so, we got

\lim_{x \to 1} f(x)=f(1) =4

so, this is continuous at x=1

Hence , option-D...........................Answer

5 0
3 years ago
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