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Marizza181 [45]
3 years ago
13

How do I solve this equation: 7x-4=3+8x

Mathematics
2 answers:
marusya05 [52]3 years ago
6 0

Answer:

x=-7

Step-by-step explanation:

Step 1: Simplify both sides of the equation.

7x−4=3+8x

7x+−4=3+8x

7x−4=8x+3

Step 2: Subtract 8x from both sides.

7x−4−8x=8x+3−8x

−x−4=3

Step 3: Add 4 to both sides.

−x−4+4=3+4

−x=7

Step 4: Divide both sides by -1.

−x/−1=7/−1

x=−7

Vlad [161]3 years ago
3 0
The answer to this is no solution

Step by step:
7x - 4 = 3 + 8x
-7x -7x
-4 = 3 + 1x
+4 +4
7 + 1x = no solution
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a 1ft long piece of wire needs to be divided into two pieces which will form the shape of a circle and a square. Determine the l
yan [13]

Answer:

Length of wire for circle is 0.44 ft

Length of wire for square is 0.56 ft

Step-by-step explanation:

Let x is circumference of the circle

then

(1-x) = perimeter of the square

Find the radius of the circle

r =  (x/2.π)

Find the area of the circle

a =  π(x/2π)^2

a =  π(x^2/4π^2)

Cancel π

a =  x^2/4π

Find the area of the square:

a =  (1-x/4)^2

a =  (1-2x+x^2)/16

Total area

A =  (x^2/4π)+(1-2x+x^2/16)

A = 4x^2+3.142-6.284x+3.142x^2

A = 7.142x^2-6.284x+3.142

Find the axis of symmetry [x = -b/(2a)]

x =  -(-6.284)/{2.(7.142)}

x =  6.284/14.284

x = 0.44 ft, the piece of wire creating a circle

and

1 - 0.44 = 0.56 ft, the piece of wire creating the square

These lengths should give minimum area of the circle and square together

7 0
3 years ago
Determine whether the fractions 3/6 and 2/4 are equivalent
omeli [17]

Answer:

They are equivalent

Step-by-step explanation:

3/6 is equal to 1/2

2/4 is equal to 1/2

5 0
3 years ago
Which equation in slope intercept represents the line that goes through the points (-1, 6) and (1, -2)
Afina-wow [57]

Answer:

D) y=-4x+2

Step-by-step explanation:

m=(y2-y1)/(x2-x1)

m=(-2-6)/(1-(-1))

m=-8/(1+1)

m=-8/2

m=-4

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y-6=-4(x+1)

y=-4x-4+6

y=-4x+2

3 0
3 years ago
Three populations have proportions 0.1, 0.3, and 0.5. We select random samples of the size n from these populations. Only two of
IRINA_888 [86]

Answer:

(1) A Normal approximation to binomial can be applied for population 1, if <em>n</em> = 100.

(2) A Normal approximation to binomial can be applied for population 2, if <em>n</em> = 100, 50 and 40.

(3) A Normal approximation to binomial can be applied for population 2, if <em>n</em> = 100, 50, 40 and 20.

Step-by-step explanation:

Consider a random variable <em>X</em> following a Binomial distribution with parameters <em>n </em>and <em>p</em>.

If the sample selected is too large and the probability of success is close to 0.50 a Normal approximation to binomial can be applied to approximate the distribution of X if the following conditions are satisfied:

  • np ≥ 10
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The three populations has the following proportions:

p₁ = 0.10

p₂ = 0.30

p₃ = 0.50

(1)

Check the Normal approximation conditions for population 1, for all the provided <em>n</em> as follows:

n_{a}p_{1}=10\times 0.10=1

Thus, a Normal approximation to binomial can be applied for population 1, if <em>n</em> = 100.

(2)

Check the Normal approximation conditions for population 2, for all the provided <em>n</em> as follows:

n_{a}p_{1}=10\times 0.30=310\\\\n_{c}p_{1}=50\times 0.30=15>10\\\\n_{d}p_{1}=40\times 0.10=12>10\\\\n_{e}p_{1}=20\times 0.10=6

Thus, a Normal approximation to binomial can be applied for population 2, if <em>n</em> = 100, 50 and 40.

(3)

Check the Normal approximation conditions for population 3, for all the provided <em>n</em> as follows:

n_{a}p_{1}=10\times 0.50=510\\\\n_{c}p_{1}=50\times 0.50=25>10\\\\n_{d}p_{1}=40\times 0.50=20>10\\\\n_{e}p_{1}=20\times 0.10=10=10

Thus, a Normal approximation to binomial can be applied for population 2, if <em>n</em> = 100, 50, 40 and 20.

8 0
3 years ago
A car travels 320 miles on 15 gasoline. The best estimate if the cars mile per gallon is
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Answer:

21.333 miles per gallon

Step-by-step explanation:

3 0
4 years ago
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