Answer:
The surface area of the model pyramid is 
Step-by-step explanation:
we know that
The surface area of the pyramid is equal to
where
B is the area of the base of the pyramid
LA is the lateral surface of the pyramid
<em>Find the area of the base B</em>
-----> is a square
<em>Find the lateral surface area of the pyramid LA</em>
we know that
The lateral surface area is equal to the area of its four triangular faces
![LA=4[\frac{1}{2}(11)(15)]=330\ in^{2}](https://tex.z-dn.net/?f=LA%3D4%5B%5Cfrac%7B1%7D%7B2%7D%2811%29%2815%29%5D%3D330%5C%20in%5E%7B2%7D)
<em>Find the surface area of the pyramid</em>
Substitute the values
answer: n=7
work:
6n-14=3n+7
6n-14 (+14) = 3n+7 (+14) add 14 to both sides
6n=3n+21
6n(-3n)=3n(-3n)+21 subtract 3 from both sides
3n=21
3n/3= 21/3 divide by 3 on both sides
n=7
Answer:
we can't see the graph
Step-by-step explanation:
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Answer:
Quotient = x - 7
Step-by-step explanation:
We are dividing x^2 - 5x +8 by x + 2
x + 2√x^2 - 5x + 8
Starting with dividing by x
x - 7
x + 2√ x^2 - 5x + 8
Multiplying x by x + 2
x
x + 2√ x^2 - 5x + 8
-
x^2 + 2x
= -7x + 8
Step ii, pick -7 for division
-7x + 8
-
-7x - 14
= +8 -(-14)
= 8+14
= 22
The answer is
( x - 7) remainder 22
(x - 7) is the quointent
22 is the remainder
9514 1404 393
Answer:
y = 1 · 5^x
Step-by-step explanation:
Use the given values in the given formula and solve for 'a' and 'b'.
y = a·b^x
5 = a·b^1 . . . . . . for (x, y) = (1, 5)
125 = a·b^3 . . . . for (x, y) = (3, 125)
Divide the second equation by the first:
125/5 = (a·b^3)/(a·b^1)
25 = b^2 . . . simplify
5 = b . . . . . . . take the square root
Substituting into the first equation, we can find 'a':
5 = a·5
1 = a . . . . . . . divide by 5
Written in the given form, the equation is ...
y = 1 · 5^x
