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Ratling [72]
3 years ago
10

Fill in the missing number. 6 x 4 =( x 4) + (3 x 4)

Mathematics
1 answer:
amid [387]3 years ago
7 0

Answer:

6x4= 24

x4)+(3x4)=12

bsnskzifkznsnaksifi

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Find the radius of a circle, when the diameter is 29 cm​
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14.5cm

Step-by-step explanation:

radius is half of diameter

29 / 2 = 14.5

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What is the solution to the given inequality?
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Step-by-step explanation:

Your answer is correct

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A parabola has its focus at (1,2) and its directrix is y=-2. the equation of this parabola could be
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<span>x^2/8 - x/4 + 1/8 = 0 A parabola is defined as the set of all points such that each point has the same distance from the focus and the directrix. Also the parabola's equation will be a quadratic equation of the form ax^2 + bx + c. So if we can determine 3 points on the parabola, we can use those points to calculate the desired equation. First, let's draw the shortest possible line from the focus to the directrix. The midpoint of that line will be a point on the desired parabola. Since the slope of the directrix is 0, the line will have the equation of x=1. This line segment will be from (1,2) to (1,-2) and the midpoint will be ((1+1)/2, (2 + -2)/2) = (2/2, 0/2) = (1,0). Now for the 2nd point, let's draw a line that's parallel to the directrix and passing through the focus. The equation of that line will be y=2. Any point on that line will have a distance of 4 from the directrix. So let's give it an x-coordinate value of (1+4) = 5. So another point for the parabola is (5,2). And finally, if we subtract 4 instead of adding 4 to the x coordinate, we can get a third point of 1-4 = -3. So that 3rd point is (-3,2). So we now have 3 points on the parabola. They are (1,0), (5,2), and (-3,2). Let's create some equations of the form ax^2 + bx + c = y and then substitute the known values into those equations. SO ax^2 + bx + c = y (1) a*1^2 + b*1 + c = 0 (2) a*5^2 + b*5 + c = 2 (3) a*(-3)^2 + b*(-3) + c = 2 Let's do the multiplication for those expressions. So (4) a + b + c = 0 (5) 25a + 5b + c = 2 (6) 9a - 3b + c = 2 Equations (5) and (6) above look interesting. Let's subtract (6) from (5). So 25a + 5b + c = 2 - 9a - 3b + c = 2 = 16a + 8b = 0 Now let's express a in terms of b. 16a + 8b = 0 16a = -8b a = -8b/16 (7) a = -b/2 Now let's substitute the value (-b/2) for a in expression (4) above. So a + b + c = 0 -b/2 + b + c = 0 And solve for c -b/2 + b + c = 0 b/2 + c = 0 (8) c = -b/2 So we know that a = -b/2 and c = -b/2. Let's substitute those values for a and c in equation (5) above and solve for b. 25a + 5b + c = 2 25(-b/2) + 5b - b/2 = 2 -25b/2 + 5b - b/2 = 2 2(-25b/2 + 5b - b/2) = 2*2 -25b + 10b - b = 4 -16b = 4 b = -4/16 b = -1/4 So we now know that b = -1/4. Using equations (7) and (8) above, let's calculate a and c. a = -b/2 = -(-1/4)/2 = 1/4 * 1/2 = 1/8 c = -b/2 = -(-1/4)/2 = 1/4 * 1/2 = 1/8 So both a and c are 1/8. So the equation for the parabola is x^2/8 - x/4 + 1/8 = 0 Let's test to make sure it works. First, let's use an x of 1. x^2/8 - x/4 + 1/8 = y 1^2/8 - 1/4 + 1/8 = y 1/8 - 1/4 + 1/8 = y 1/8 - 2/8 + 1/8 = y 0 = y And we get 0 as expected. Let's try x = 2 x^2/8 - x/4 + 1/8 = y 2^2/8 - 2/4 + 1/8 = y 4/8 - 1/2 + 1/8 = y 4/8 - 1/2 + 1/8 = y 1/2 - 1/2 + 1/8 = y 1/8 = y. Let's test if (2,1/8) is the same distance from both the focus and the directrix. The distance from the directrix is 1/8 - (-2) = 1/8 + 2 = 1/8 + 16/8 = 17/8 The distance from the focus is d = sqrt((2-1)^2 + (1/8-2)^2) d = sqrt(1^2 + -15/8^2) d = sqrt(1 + 225/64) d = sqrt(289/64) d = 17/8 And the distances match again. So we do have the correct equation of: x^2/8 - x/4 + 1/8 = 0</span>
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3 years ago
For each of these triples, find if they could be the lengths of the sides of a right triangle.
frutty [35]
A is the correct answer
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4 years ago
Classify the polynomial according to its degree and number of terms 3x^2+8x​
Sunny_sXe [5.5K]

Answer:

Classifying Polynomials

Polynomials can be classified two different ways - by the number of terms and by their degree.

1. Number of terms.

A monomial has just one term. For example, 4x2 .Remember that a term contains both the variable(s) and its coefficient (the number in front of it.) So the is just one term.

A binomial has two terms. For example: 5x2 -4x

A trinomial has three terms. For example: 3y2+5y-2

Any polynomial with four or more terms is just called a polynomial. For example: 2y5+ 7y3- 5y2+9y-2

Practice classifying these polynomials by the number of terms:

1. 5y

2. 3x2-3x+1

3. 5y-10

4. 8xy

5. 3x4+x2-5x+9

Answers: 1) Monomial 2) Trinomial 3) Binomial 4) Monomial 5) Polynomial

2. Degree. The degree of the polynomial is found by looking at the term with the highest exponent on its variable(s).

Examples:

5x2-2x+1 The highest exponent is the 2 so this is a 2nd degree trinomial.

3x4+4x2The highest exponent is the 4 so this is a 4th degree binomial.

8x-1 While it appears there is no exponent, the x has an understood exponent of 1; therefore, this is a 1st degree binomial.

5 There is no variable at all. Therefore, this is a 0 degree monomial. It is 0 degree because x0=1. So technically, 5 could be written as 5x0.

3x2y5 Since both variables are part of the same term, we must add their exponents together to determine the degree. 2+5=7 so this is a 7th degree monomial.

Classify these polynomials by their degree.

1.7x3+52+1

2.6y5+9y2-3y+8

3.8x-4

4.9x2y+3

5.12x2

Answers 1) 3rd degree 2) 5th degree 3) 1st degree 4) 3rd degree 5) 2nd degree

6 0
3 years ago
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