What is the tangent of 210 degrees?

Katena32 [7]

After solving for both variables, you find that each bus can hold 59 students and each van can hold 18 students.

Step-by-step explanation:

You can find the amount of students each vehicle can carry by representing the two scenarios in equations.

You are trying to find how many students will fit in each bus or van, so the two variables used will be "b" to represent how many students can fit in a bus and "v" to represent how many students can fit in a van.

High school A used 1 van and 6 buses, so there will be 1"v" and 6"b" for 372 students.

High school B used 4 vans and 12 buses, so there will be 4"v" and 12"b" for 780 students.

Now, represent these in equations:

$v+6b = 372\\4v + 12b = 780$

We can use substitution to solve this system:

$v + 6b = 372$ can be rewritten as $v = 372 - 6b$ after subtracting 6b from both sides. You can then substitute this new value of "v" into the other equation to solve for "b":

$4(372-6b) + 12b = 780\\1488 - 24b + 12b = 780\\1488 - 12b = 780\\-12b = -708\\b = 59$

After solving for b, you can then substitute the new value of b into the other equation to find the value of v:

$v + 6(59) = 372\\v + 354 = 372\\v = 18$

After solving for both variables, you find that each bus can hold 59 students and each van can hold 18 students.

5 0

3 years ago

Read 2 more answers

Karls mother buys 60 party favors to give out as a fift during karls birthday party which number of guest will not let her divid

xeze [42]

THE answer is 15 just look it up

7 0

3 years ago

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The diagram shows the cross-section of a wall of a cinema. It has to be painted. Work out the area that needs to be painted.

mestny [16]

Answer:

Area = 370 m²

Cost to paint = £105

Step-by-step explanation:

Area of the wall of a cinema hall = Area of a trapezoid (1)+ Area of a rectangle (2) + Area of a trapezoid (3)

Area of a trapezoid = $\frac{1}{2}(b_1+b_2)h$

where $b_1$ and $b_2$ are the parallel sides and h is the distance between these sides.

Area of trapezoid (1) = $\frac{1}{2}(11+12)\times 6$

= 69 m²

Area of the rectangle (2) = Length × Width

= 12 × 15

= 180 m²

Area of the trapezoid (3) = $\frac{1}{2}(12+10)\times 11$

= 121 m²

Now area of the wall = 69 + 180 + 121

= 370 m²

One tin covers the area = 25 m²

Number of tins required to paint the wall = $\frac{\text{Total area}}{\text{Area covered by one tin}}$

= $\frac{370}{25}$

= 14.8

Therefore, number of tins to be purchased = 15

Cost to paint the complete wall = 15 × £7

= £105

8 0

3 years ago

What is 180% as a decimal

bazaltina [42]

Answer:

1.80 this is the correct answer

7 0

3 years ago

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The board of an internet start up company has sixteen members. if one person is in charge of research and one is in charge of ma

Brilliant_brown [7]

The number of ways in which the position of one person in charge of research and one person in charge of marketing can be chosen from the board of 16 members is <u>240 ways</u>. Computed using permutations.

The permutation is the way of choosing a set of objects from a larger set of objects in a specific sequence.

If we are choosing r number of objects, from n number of objects in a specific sequence, then we follow permutation, and it is given as:

nPr = n!{(n - r)!}.

In the question, we are asked to find the number of ways in which the position of one person in charge of research and one person in charge of marketing can be chosen from the board of 16 members.

Since the position is to be chosen in a specific order, we will follow permutation.

The number of positions to be chosen (r) = 2.

The number of members (n) = 16.

Thus, the number of ways is given as:

nPr = n!{(n - r)!},

or, 16P2 = 16!{(16 - 2)!},

or, 16P2 = 16!/14! = 15*16 = 240.

Thus, the number of ways in which the position of one person in charge of research and one person in charge of marketing can be chosen from the board of 16 members is <u>240 ways</u>. Computed using permutations.

Learn more about permutations at

brainly.com/question/4658834

#SPJ4

6 0

2 years ago