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suter [353]
3 years ago
15

Jonathan is in a class of 15 boys and 35 girls.40%of the students in the class take the bus to school how many students do not t

ake the bus to school ?
Mathematics
2 answers:
sertanlavr [38]3 years ago
7 0
40% of 40
10% of 40 is 4
4 x 4=16
40-16 =24
Answer is 24
Svetllana [295]3 years ago
6 0
15 + 35 to find the total of students in the class which is 50.
100 / 40 = 2.5, so divide 50 by 2.5 and you get 20

Answer is 20
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Thepotemich [5.8K]
From my own solution, my answer is closest to D<span>. 1951 yd; 27°
</span><span>
The boat is 1951 yards away from the observer in tower B. The angle of depression to the boat from Tower B is 27</span>°.<span>

Pls. see my attachment. 

In it I divided the big triangle into two small right triangles. 
I solved for the common leg of the right triangles by using sin theta formula. sin </span>θ = opposite / hypotenuse
<span>
sin 35</span>° = opposite / 1538 yd
<span>sin 35</span>° * 1538 yd = opposite
<span>882.16 yd = opposite

From there, I used the Pythagorean theorem to solve for the missing side which is part of the 3,000 yd measure.

I got the measure of 1,259.86 yards. The remaining measure of 1,740.14 is the side of the other right triangle. 

Still using Pythagorean Theorem, I used the measurement of the known side of the 2nd right triangle to solve for its hypotenuse which was 1,950.97 or 1,951 yards.

With regards to the angle of depression, I used this formula:

tan(y) = opposite / adjacent
tan(y) = 1538 yd / 3000 yd
tan(y) = 0.513
y = 0.513/tan
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</span>

8 0
3 years ago
Amanda created a table to help her represent the sample space of spinning a spinner and flipping a coin.
OlgaM077 [116]

Answer:

\sf \dfrac{1}{8}

Step-by-step explanation:

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Coin choices: Heads, Tails

\large\begin{array}{| c | c | c | c | c |}\cline{1-5} & \sf Red & \sf Green & \sf Yellow & \sf Blue\\\cline{1-5} \sf Heads & RH & GH &YH & BH \\\cline{1-5} \sf Tails &RT & GT& YT& BT\\\cline{1-5}\end{array}

\sf Probability\:of\:an\:event\:occurring = \dfrac{Number\:of\:ways\:it\:can\:occur}{Total\:number\:of\:possible\:outcomes}

\implies \sf P(blue)=\dfrac{1}{4}

\implies \sf P(heads)=\dfrac{1}{2}

\implies \sf P(blue)\:and\:P(heads)=\dfrac{1}{4} \times \dfrac{1}{2}=\dfrac{1}{8}

5 0
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