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anyanavicka [17]
3 years ago
14

Convert 5 kilograms to grams

Mathematics
2 answers:
konstantin123 [22]3 years ago
7 0
5,000 grams
1 kilogram=1,000 grams
ss7ja [257]3 years ago
5 0

Answer:

5000

Step-by-step explanation:

hmu if you need more help! :D

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6:
schepotkina [342]

Answer:

$52.5

Step-by-step explanation:

Whenever there is a sales tax of a certain percentage, you need to first convert that percentage to decimal. 5%=0.05, and multiplying this by the overall price gives 0.05*50=$2.5. Adding this to the initial price of $50, you get 50+2.5=$52.5. Hope this helps!

4 0
3 years ago
Read 2 more answers
Describe the error in the work shown below.
Katena32 [7]

Answer:

the bottom equation should be 18+30=3(6+10)

Step-by-step explanation:

6(3+10) = 18+60 which equals 78

78 does not equal 18

5 0
3 years ago
1) 24 + m = 49 pls help​
Doss [256]

Answer:25

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
How many times does the graph of the function below intersect touch the x-axis? y= -3x^2 + x + 4
inessss [21]

Answer:

2 times

Step-by-step explanation:

Well let's first graph the quadratic equation,

Look at the image below ↓

By looking at the image below we can tell that the graph touches the x axis 2 times at,

<u>(-1,0)</u>

<u>(1 1/3,0)</u>

<em />

<em>Thus,</em>

<em>the parabola touches the x axis twice.</em>

<em />

<em>Hope this helps :)</em>

6 0
3 years ago
A projectile is fired at such an angle that the vertical
svetoff [14.1K]

(a) The projectile remains in the air for 10 seconds

(b) It travels a horizontal distance of 600 meters

Step-by-step explanation:

A projectile is fired at such an angle that

1. The vertical  component of its velocity is 49 m/sec

2. The horizontal  component of its velocity is 60 m/sec

We need to find:

(a) How long the projectile remains in the air

(b) The horizontal distance it travels

∵ The vertical distance y = u_{y} t - \frac{1}{2} g t², where

u_{y} is the vertical  component of its velocity, g is the acceleration

of gravity and t is the time

∵ y = 0 ⇒ it return to the same initial height

∵ u_{y} = 49 m/s

∵ g = 9.8 m/s²

- Substitute these values in the rule above

∴ 0 = 49 t - \frac{1}{2} (9.8) t²

∴ 0 = 49 t - 4.9 t²

- Take t as a common factor

∴ 0 = t (49 - 4.9 t)

- Equate each term by 0

∴ t = 0 ⇒ at initial position

∴ 49 - 4.9 t = 0

- Add 4.9 t to both side

∴ 49 = 4.9 t

- Divide both sides by 4.9

∴ t = 10 seconds

(a) The projectile remains in the air for 10 seconds

∵ The horizontal distance = u_{x} t, where u_{x} is the

   horizontal component of its velocity

∵ u_{x} = 60 m/sec

∵ t = 10 seconds

∴ x = 60 × 10 = 600 meters

(b) It travels a horizontal distance of 600 meters

Learn more:

You can learn more about the component of velocity in brainly.com/question/4464845

#LearnwithBrainly

3 0
3 years ago
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