Answer:
See below
Step-by-step explanation:
(a) Field lines
A negatively charged particle has an electric field associated with it.
The field lines spread out radially from the centre of the point. They are represented by arrows pointing in the direction that a positive charge would move if it were in the field.
Opposite charges attract, so the field lines point toward the centre of the particle.
For an isolated negative particle, the field lines would look like those in Figure 1 below.
If two negative charges are near each other, as in Figure 2, the field lines still point to the centre of charge.
A positive charge approaching from the left is attracted to both charges, but it moves to the closer particle on the left.
We can make a similar statement about appositive charge approaching from the left.
Thus, there are few field lines in the region between the two particles.
(b) Coulomb's Law
The formula for Coulomb's law is
F = (kq₁q₂)/r²
It shows that the force varies inversely as the square of the distance between the charges.
Thus, the force between the charges decreases rapidly as they move further apart.
First subtract manny value 36.5 from Evan values 18 which will give u 18.5 cm which then u have to convert. Since 1 cm is about .4, we can multiply 18.5 by .4 to get the answer 7.4 inches
Answer:
Step-by-step explanation:
the answer is 25.00 hope this helps
Hey there!
2(p + 1) + 8(p - 1) = 5p
2(p) + 2(1) + 8(p) + 8(-1) = 5p
2p + 2 + 8p - 8 = 5p
10p - 6 = 5p
SUBTRACT 5p to BOTH SIDES
10p - 6 - 5p = 5p - 5p
SIMPLIFY IT!
5p - 6 = 0
ADD 6 to BOTH SIDES
5p - 6 + 6 = 0 + 6
CANCEL out: -6 + 6 because it gives you 0
KEEP: 0 + 6 because it helps solve for the p-value
5p = 0 + 6
5p = 6
DIVIDE 5 to BOTH SIDES
5p/5 = 6/5
CANCEL out: 5/5 because it gives you 1
KEEP: 6/5 because gives you the result of the p-value
SIMPLIFY IT!
p = 6/5
Therefore, your answer is: p = 6/5
Good luck on your assignment and enjoy your day!
~Amphitrite1040:)
Y = mx + c
y = 2x + c
When x = 5 and y = 0,
0 = 2(5) + c
c = -10
y = 2x - 10