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3 years ago

If i have 20 questions on my test and 65% is a passing grade how many do i need to get right

Mathematics

2 answers:

mrs_skeptik [129]3 years ago

8 0

13.

65% = 65/100, and 65/100 * 20 = 13

Rina8888 [55]3 years ago

5 0

You would need to answer 13 out of 20 questions to get 65%.

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-4x-2y=-12 solve the system of equations

Blababa [14]

Um there needs to be another equation

3 0

3 years ago

What is the area of the trapezoid?

Maslowich

<h3>Given Information :</h3>

Length of parallel sides = 60 ft and 40 ft
Height of the trapezoid = 30 ft

<h3>To calculate :</h3>

Area of the trapezoid.

<h3>Calculation :</h3>

As we know that,

$\bigstar \: \boxed{\sf {Area_{(Trapezium)} = \dfrac{1}{2} \times ( a + b) \times h}} \\$

a and b are length of parallel sides.
h denotes height.

Substituting values, we get :

$\longmapsto$ Area = $\sf \dfrac{1}{2}$ × ( 60 + 40 ) × 30 ft $\sf ^2$

$\longmapsto$ Area = $\sf \dfrac{1}{2}$ × 100 × 30 ft $\sf ^2$

$\longmapsto$ Area = 1 × 100 × 15 ft $\sf ^2$

$\longmapsto$ Area = 100 × 15 ft $\sf ^2$

$\longmapsto$ Area = 1500 ft $\sf ^2$

Therefore,

Area of the trapezoid is 1500 ft $\sf ^2$

6 0

3 years ago

There are 276 students.

Lynna [10]

Step-by-step explanation:

Number of males is

276 - 158 = 118

Number of males not enrolled

118 - 82 = 36

Number of females not enrolled

158 - 102 = 56

(a)

The table based on data is

Enrolled Not enrolled Total

Male 82 36 118

Female 102 56 158

Total 184 92 276

(b)

Percentage of students were males that went to magic college

enrolled male / total students = (use table above)
82/276*100% = 29.71% (rounded)

(c)

Percentage of females went to magic college

enrolled female / total female = (use table above)
102/158*100% = 64.56% (rounded)

7 0

2 years ago

The size of the left upper chamber of the heart is one measure of cardiovascular health. When the upper left chamber is enlarged

Temka [501]

Answer:

a) 0.283 or 28.3%

b) 0.130 or 13%

c) 0.4 or 40%

d) 30.6 mm

Step-by-step explanation:

z-score of a single left atrial diameter value of healthy children can be calculated as:

z= $\frac{X-M}{s}$ where

X is the left atrial diameter value we are looking for its z-score

M is the mean left atrial diameter of healthy children (26.7 mm)

s is the standard deviation (4.7 mm)

Then

a) proportion of healthy children who have left atrial diameters less than 24 mm

=P(z<z*) where z* is the z-score of 24 mm

z*= $\frac{24-26.7}{4.7}$ ≈ −0.574

And P(z<−0.574)=0.283

b) proportion of healthy children who have left atrial diameters greater than 32 mm

= P(z>z*) = 1-P(z<z*) where z* is the z-score of 32 mm

z*= $\frac{32-26.7}{4.7}$ ≈ 1.128

1-P(z<1.128)=0.8703=0.130

c) proportion of healthy children have left atrial diameters between 25 and 30 mm

=P(z(25)<z<z(30)) where z(25), z(30) are the z-scores of 25 and 30 mm

z(30)= $\frac{30-26.7}{4.7}$ ≈ 0.702

z(25)= $\frac{25-26.7}{4.7}$ ≈ −0.362

P(z<0.702)=0.7587

P(z<−0.362)=0.3587

Then P(z(25)<z<z(30)) =0.7587 - 0.3587 =0.4

d) to find the value for which only about 20% have a larger left atrial diameter, we assume

P(z>z*)=0.2 or 20% where z* is the z-score of the value we are looking for.

Then P(z<z*)=0.8 and z*=0.84. That is

0.84= $\frac{X-26.7}{4.7}$ solving this equation for X we get X=30.648

5 0

3 years ago

What is the coefficient of q (2/3q-3/4) and -1/6q-r)

kirza4 [7]

The coefficient in (2/3q-3/4) is 2/3 and in (-1/6q-r) is -1/6

4 0

3 years ago