6.0⋅<span>102</span><span>kg m<span>−3</span></span>
Explanation:
In order to find the density of the bowling ball, <span>ρ
</span>, you must determine the mass one unit of volume of this bowling ball would have.
Notice that the problem provides you with the volume of the bowling ball expressed cubic meters, <span><span>m3</span>
</span>, which means that one unit of volume would be <span><span>1 m3</span>
</span>.
Now, you know that a volume of <span><span>0.0050 m3</span>
</span> has a mass of <span>3.0 kg
</span>. You can use this known proportion as a conversion factor to figure the mass of <span><span>1 m3</span>
</span>
<span><span>1<span>m3</span>⋅<span>3.0 kg<span>0.0050<span>m3</span></span></span>=600 kg</span>
</span>
So, you know that one unit of volume has a mass of <span>600 kg
</span>, which means that the bowling ball's density is equal to
<span><span><span>ρ=6.0⋅<span>102</span><span>kg m<span>−3</span></span></span><span>−−−−−−−−−−−−−−−−−</span></span>
</span>
The answer is rounded to two sig figs.
30%of 68 = 30/100*68= 3*68/10=204/10=20.4
The answer is D, 8$. One easy way to do it is to take 10% of 40, which is 4, and double it.
V=l x w x h not too sure if you're given any numbers
If it has the negative so the answer will be negative but if it doesn't have the negative so the answer is positive because if you want to find the m you should divide the both sides of the equation by the factor of m:
-4m = 1.75 ⇒ -4m/-4 = 1.75/-4 ⇒ m = 1.75/-4 ⇒ m = -0.4375
4m = 1.75 ⇒ 4m/4 = 1.75/4 ⇒ m = 1.75/4 ⇒ m = 0.4375 :)))
i hope this is helpful
have a nice day
