Calculate the average rate of change of the function g over the interval-2 A)-4<br> B)-1<br> C)0<br> D)1

5) Answer the following questions :

uysha [10]

Answer:

a)9:7 b) 9:16 c) 7:16

Step-by-step explanation:

the no of girls (320-180)=140

a) ratio of no of boys and girls=180/140=9/7=9:7

b)ratio of boys and total pupil=180/320=9/16=9:16

c) ratio of the girls and pupils=140/320=7/16=7:16

6 0

3 years ago

Read 2 more answers

Shelia's measured glucose level one hour after a sugary drink varies according to the normal distribution with μ = 117 mg/dl and

TiliK225 [7]

Answer:

The level L such that there is probability only 0.01 that the mean glucose level of 6 test results falls above L is L = 127.1 mg/dl.

Step-by-step explanation:

To solve this problem, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central limit Theorem

The Central Limit Theorem estabilishes that, for a random variable X, with mean $\mu$ and standard deviation $\sigma$ , a large sample size can be approximated to a normal distribution with mean $\mu$ and standard deviation $\frac{\sigma}{\sqrt{n}}$

In this problem, we have that:

$\mu = 117, \sigma = 10.6, n = 6, s = \frac{10.6}{\sqrt{6}} = 4.33$

What is the level L such that there is probability only 0.01 that the mean glucose level of 6 test results falls above L ?

This is the value of X when Z has a pvalue of 1-0.01 = 0.99. So X when Z = 2.33.

$Z = \frac{X - \mu}{\sigma}$

By the Central Limit Theorem

$Z = \frac{X - \mu}{s}$

$2.33 = \frac{X - 117}{4.33}$

$X - 117 = 2.33*4.33$

$X = 127.1$

The level L such that there is probability only 0.01 that the mean glucose level of 6 test results falls above L is L = 127.1 mg/dl.

6 0

4 years ago

7. Write the following proportion: 8 is to 64 as 2 is to X

Paul [167]

2 is to 4 because 64/8 is 8. 4/2 is 2. 2 x 2 is in proportion to 8 x 8

4 0

4 years ago

Read 2 more answers

Q = 15<br> a = 16<br> What would you do with q and a to get 240?

ch4aika [34]

You multiply Q and a to get 240, because 15 x 16 = 240.

6 0

4 years ago

What is the slope of line a? <br><br>

emmainna [20.7K]

<h3>Answer: -1/4 (choice C)</h3>

========================================================

Explanation:

Start at the point (0,1). This is the y intercept, which is where the graph crosses the y axis.

Then move down 1 and over to the right 4 spaces. We arrive at (4,0) which is the x intercept.

The process of "down 1, over to the right 4" can be thought of like this

rise/run = -1/4

rise = -1

run = 4

A rise of -1 indicates we go down 1 unit

The run of 4 means we move to the right 4 units

So that's why slope = rise/run = -1/4

-------------------------------------------------------

Here's another approach using the slope formula:

m = (y2-y1)/(x2-x1)

m = (0-1)/(4-0)

m = -1/4

I used the two points (0,1) and (4,0) as (x1,y1) and (x2,y2) respectively. This formula basically says "subtract the y coordinates, subtract the x coordinates in the same order, then divide the differences y over x".

-------------------------------------------------------

Side note: The line moving downhill, as we read from left to right, indicates a negative slope.

5 0

3 years ago

Calculate the average rate of change of the function g over the interval-2 A)-4 B)-1 C)0 D)1