A = P(1+r)^t
A = amount made after the specified time
P = original amount of money
r = rate
t = time

2500 = 1800 (1 + r)^2
2500/1800=(1800(1+r)^2)/1800
1.3888 = (1+r)^2
1.17851 = (1 +r)
1.17851 - 1 = r
Rate = .17851

7 0

3 years ago

Need help with number 3a and 3b ?

kow [346]

Answer:

4 and 4.1

Step-by-step explanation:

because sqrrt17 is about 4.123 (memmorized) and it's rounded down to 4 and down to 4.1

8 0

3 years ago

What is the zeros of function of f(x)=2x+2

chubhunter [2.5K]

The answer is there !!!

6 0

3 years ago

in a poll about work, 62% of respondents said that their jobs were sometimes or always stressful. twelve workers are chosen at r

Sladkaya [172]

The mean and standard deviation of number who find their jobs stressful are 7.44 and 1.6814 respectively.

Given,

number of workers chosen , n=12

percentage of respondents =62%

from given data the calculation are done according to binomial distribution,

then,

probability of respondents , $p=\frac{62}{100}=0.62$

a)calculating mean,

$\mu=n*p\\\\\mu=12*0.62\\\\\mu=7.44$

b)calculating standard deviation,

$\sigma=\sqrt{n*p*(1-p)}\\\\\sigma=\sqrt{12*0.62*(1-0.62)}\\\\\sigma=\sqrt{7.44(0.38)}\\\\\sigma=\sqrt{2.8272}\\\\\sigma=1.6814$

Thus, the mean and standard deviation of number who find their jobs stressful are 7.44 and 1.6814 respectively.

To learn more about binomial distribution refer here

brainly.com/question/15303817

#SPJ4

8 0

1 year ago